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If a 325 watt heater has a current of 6.0A what is the resistance?
Watts = Current x Volts with your resistive heat application. To figure out resistance you need to know voltage and current. Since you are drawing 6 amps then Volts = 325/6. This means that there is about 54 volts supplying the heater which seems like a very strange supply voltage. Since Volts = Current x Resistance the resistance = 325/36.
What is the voltage power current and resistance of an electrical heater?
The two most important ratings for an electrical heater are its rated power and its rated voltage, and these will be printed on a 'nameplate' fixed somewhere on the heater (e.g. '3 kW at 230 V').For the heater to operate at its rated power, it must be subject to its rated voltage. In the above example, the heater will only operate at 3 kW if it is supplied with 230 V.If you know the heater's power (P) and its voltage (U), then you can calculate the rated current (I) it will draw from the supply, using the equation: I = P/U.You can also determine its resistance (R), using the equation R = U2/P.
Explain why an electric bulb becomes dim when an electric heater in parallel circuit is made onWhy dimness decreases after some time?
this happen due to sudden amount of voltage drop in the main feeder due to large current drawn by the heater , so this drop in voltage will let the bulb operate by avltage of a mount (V-Vd) [where V represent the supply voltage and Vd represent the voltage drop in the main feeder of the circuit] , which is less than the voltage before the heater is connected and due to this situation the current passes through the wire of the bulb will be less and therefore the brightness of the bulb becomes dim.after a while the wire of the heater will has high temperature which increase its resistance and due to this the current drawn by the heater will decrease than the current at the first time , therefore the drop in voltage will also decrease , which implise increase in current drawn by the bulb and therefore the dimness decrease .
A toaster draws 8 A of current with a voltage of 120 V?
The voltage is the main power of a toaster!! but if the current flow is low the heat of the toaster is less heat that you expect, the 8 A is right for your toaster!!!
What voltage would you expect to measure across closed switch?
Original Correct Answer:The voltage across an open switch should equal the supply voltage.More Detailed Answer:The above answer is basically correct. However, it may not be EXACTLY the supply voltage.This is counter-intuitive at first glance and confuses a lot of people, including electrical engineers. The reason is this. Voltage, Current and Resistance are all interrelated by Ohms Law. Voltage equals Current multiplied by Resistance.It is easy to think that since a switch is open, then you do not have current flow through the circuit. Thus, current times any Resistance is equal to zero volts because the current is equal to zero. Thus, by this logic, you would expect to find zero volts across the switch. In actuality this is true.But, when you insert you meter, you change the conditions of the circuit, and the following is the result.Let's say that you have a circuit with a resistance load like a heater, and a inductive load like a motor. The switch that powers these devices is open, thus their is no current flowing through the resistance or inductive loads.Now you put the meter across the open switch. When you do, you insert a very large resistance in parallel to the open switch. Why? Because to get volts, the meter measures current flow through a known resistance, and then calculates voltage. To keep the resistance from impacting the circuit performance, the resistance is very large. Therefore, when you insert the meter, you will get a flow of current through the meter.Because of this large resistance, the current trough the resistance load, inductive load, and wires is very small. Thus, the voltage drop across the loads and wiring is very small. Therefore, it appears that the entire voltage in the circuit is across the huge resistance in the meter. The result is a voltage reading that is very near the source voltage.Let's do the math. Let's assume you have 120 volts. You also have a resistance of 500 ohms, and a motor winding that has 0 ohms resistance when DC is applied (This is true for motors). The meter has a 10 million ohm resistance.If these loads are in series, the total resistance is 10Million 500 ohms. The 11.9 microamps. By multiplying the current flow to each resistance, you get 6 millivolts across the resistance, no voltage across the motor winding, and 119.994 across the open switch or meter. Since a meter rounds it reading, you would get 120.If the loads are in parellel, you would get the same thing, becuase the switch is in series with both loads. In this example, the motor winding would have all the current flow through it since it is zero ohms, and the parallel resitance load is 500 ohms. Thus, the total resistance is the 10 million of the meter, and this resistance drive the current, and thus the largest voltage drop is at the swtich/meter. You could decide to remove the motor from this parellel circuit. If you did then the then the result is the series circuit above.
What current will flow through the heating coil when the heater is plugged in?
The current flowing through the heating coil will depend on the resistance of the coil and the voltage of the power source. Using Ohm's Law (I = V/R), where I is the current, V is the voltage, and R is the resistance, you can calculate the current. The higher the voltage or lower the resistance, the higher the current.
What is the voltage of a small electric heater if the heater is drawing 12 amperes and has a resistance of 10 ohms?
Voltage is current times resistance, 1.2 x 110 = 132 volts.
Does increasing the voltage to an electric heater increase the amperage it draws?
It will increase the current since the water heater is made of a heating element and which is resistive in nature. Ohms law states that V=IR where V is the voltage, I the current and R the resistance. Now the resistance will always remain constant. Thus, when the voltage is increased, the current will also increase.
What is the voltage across an electric water heater element that has a resistance of 32 ohms when the current through it is 6.8A?
It is 6 times 8 and the answer is in volts.
Does heat come from the amps or the volts?
By driving current through a resistance, we create heat. But it takes voltage to drive current through a resistance. In that light, it takes both voltage and current to drive a resistance heater and get it hot. Power (watts) is current (amps) times voltage (volts). But power is also current squared (I2) times resistance (ohms), or I2R. Power is also voltage squared (E2) divided by resistance (ohms) or E2/R. To increase current through a given resistance (like a resistive heating element) you have to increase the voltage. Voltage, current and resistance are "locked" in a fixed arrangement called Ohm's law. It's a relationship that takes this form: E = I x R, or I = E/R, or R = E/I As power is amps times volts (P = I x E), we can answer the question asked here. Question: "Does heat come from the amps or the volts?" Answer: "Yes."
If a 325 watt heater has a current of 6.0A what is the resistance?
Watts = Current x Volts with your resistive heat application. To figure out resistance you need to know voltage and current. Since you are drawing 6 amps then Volts = 325/6. This means that there is about 54 volts supplying the heater which seems like a very strange supply voltage. Since Volts = Current x Resistance the resistance = 325/36.
Does resistance of heater coil remains same when current flows through it?
Typically resistance rises with temperature.
Does the resistance of heater coil remains same when current flows through it?
Typically resistance rises with temperature.
How do you compute the watt of heater with volt and resistance are the given?
You must first solve for current or amperage, if you know only voltage and resistance. The symbol for current is normally "I" or "A". The formula is A=V / R . So divide the voltage by the resistance to obtain the current. Then the formula for wattage or power (P) is P= V x A . So then you would multiply the voltage by the current to obtain the power in watts.
Will a 110 electric heater produce the same amount of heat as a 220 heater at 1000 watts?
No, a 1000-watt electric heater operating at 110V will produce the same amount of heat as a 1000-watt heater operating at 220V. The power output (in watts) determines the amount of heat produced, not the voltage.
120v how much current does a 1500w resistace heater draw?
Using the formula Power = Voltage x Current, we can calculate the current: Current = Power / Voltage. Plugging in the values, we get 1500W / 120V = 12.5A. So, a 1500W resistance heater would draw 12.5A of current at 120V.
What is the voltage power current and resistance of an electrical heater?
The two most important ratings for an electrical heater are its rated power and its rated voltage, and these will be printed on a 'nameplate' fixed somewhere on the heater (e.g. '3 kW at 230 V').For the heater to operate at its rated power, it must be subject to its rated voltage. In the above example, the heater will only operate at 3 kW if it is supplied with 230 V.If you know the heater's power (P) and its voltage (U), then you can calculate the rated current (I) it will draw from the supply, using the equation: I = P/U.You can also determine its resistance (R), using the equation R = U2/P.
