Yes, it will decrease when the same amount (n) of gas is pressurized:
Combined Gas law: V = (n.R) * T / p
(This is certainly true when done isothermically, else it also depends on temperature)
Boyle's Law. This law says that the pressure and volume of a gas are inversely related. In other words, as the pressure of a gas goes up, the volume goes down and vice versa.
As temperature goes up, the volume goes down
If you're asking about gases... Yes. If you increase the temperature without allowing the volume to change, the pressure will in fact go up as well. (If the volume is allowed to change, it's impossible to say what happens to the pressure without additional details.)
The density of water changes at different temperatures. As temperature goes up, density goes down.
Depending on your experiment, the number of moles will or will not change. If the gas is in a sealed container, then obviously the number of moles does not change. But if the gas is in an open container, then the gas is free to move. In this case, raising the temperature would cause the number of moles to go down. Because the temperature is going up, the pressure increases also. When the pressure goes up, the volume goes up, meaning the gas "wants" to spread out. In an unsealed container, the gas will leave and you will end up with less moles within the container.
Volume and pressure vary indirectly, which means that when one goes up, the other goes down. If the pressure goes up, the volume goes down. If the volume goes up, the pressure goes down.Mathematically:P1V1 = P2V2The left side represents the beginning conditions, and the right side represents the pressure and temperature that have changed. Note that this formula assumes constant mass and temperature.
If a balloon is squeezed, then that means the volume is decreasing. Volume and pressure vary indirectly, which means that when one goes up, the other goes down. So when you are decreasing the volume of the balloon, the pressure inside is going up (assuming constant mass and temperature).
The pressure increases.
For this you would use Boyle's Law, P1V1 = P2V2. The first pressure and volume variables are before the change, while the second set are after the change. In this case, the volume is being changed and the pressure has to be solved for. P1 = 1.30 ATM V1 = 31.4 L P2 = Unknown V2 = 15.0 L P1V1 = P2V2 1.30(31.4)=15.0P P= 2.72 ATM Looking at the question simply, you can get an estimate on the pressure because you can see that pressure and volume vary indirectly (if volume goes up, pressure goes down). If the volume is cut in half (roughly), then the pressure should increase by half.
If a balloon is squeezed, then that means the volume is decreasing. Volume and pressure vary indirectly, which means that when one goes up, the other goes down. So when you are decreasing the volume of the balloon, the pressure inside is going up (assuming constant mass and temperature).
With the ideal gas law PV=nRT, if n (number of molecules, R(gas constant) and T (temperature) are fixed, then the product of P (pressure) and V (volume) is also constant. So. Pressure and Volume are inversely related. If pressure goes up, volume must go down and if pressure goes down, volume must increase. The same goes with increasing or decreasing volume.
volume is the measurement of the amount of space that an object takes up.
Boyle's Law. This law says that the pressure and volume of a gas are inversely related. In other words, as the pressure of a gas goes up, the volume goes down and vice versa.
it goes up up up up =D
As temperature goes up, the volume goes down
Assuming the tank was not in a vacuum, the VOLUME stays constant. The volume is the total area inside the tank. The pressure would change when 'pumped up'. The volume would not. The pressure inside would also change based on the temperature, relative to the outside pressure.
if you're talking about gases it's all about the ideal gas law. PV = nRT so as volume goes up, pressure goes down.