which of mikes traits are heterozygous? Gg or ee or CC or Ff
heterozygous
No, only diploid organisms can be heterozygous.
An organism with two different alleles for a trait? is a hybrid
AaBb usually, but can also be AAbb or aaBB depending on what they ask you is heterozygous. To be heterozygous for one trait, it's AaBb. To have a heterozygous genotype, unless specified, it can be any of the above.
It's the gene that would be heterozygous not the chromosome.
The heterozygous genotype
There different genotypes and two different colors Black fur is dominant --> F White fur is recessive --> f The parents are bot Ff (heterozygotes, and because black fur is dominant they have a black fur). If they mate, you get parents: Ff x Ff Offspring: FF Ff Ff ff so 25% will be homozygous for Black fur 2x25=50% will be heterozygous, and have a Black fur and 25% wil be homozygous for White fur. Hence, of their offspring, 75% will have a black fur and 25% will have a white fur
Alright, I suppose I will do your homework for you.. Here is your punnet square: F F F FF FF f Ff ff Therefore, 3/4, or 75%, offspring will have the phenotype of having freckles, and 1/4, or 25% will have the phenotype of no freckles. And 2/4, or 50%, of the offspring will have the genotype for homozygous for freckles, 1/4, or 25%, of the offspring will carry a heterozygous trait for freckles, and 1/4, or 25%, of the offspring will have the phenotype for homozygous no freckles.
Child's genotype would be homozygous recessive alleles (nn) and parents would both have heterozygous dominant alleles (Nn).
We'llsay F is dominant for freckles and f is recessive for non-freckled. The father is ff The mother is Ff The child is ff. Probability of this cross producing a homozygous recessive child is 50%. There isn't a precise term for this cross.
If all of the children have freckles, that means that both parents had dominant genotypes. (Mother; FF and Father; FF). Or, one parent could have a hybrid genotype. (For example, Mother; Ff and Father; FF). Based on the outcome of a Punnett Square, either one parent must have a hybrid and the other dominant, or both must have dominant genotypes.
FF-FF-FF-FF-FF-FF
all dominant
ffffff
That's called the "MAC address" or "Hardware address". It's a unique set of numbers assigned to a network device. Anything that access the internet whether phones, wireless cards, computers, etc, all have a MAC address. The address with all one's (FF-FF-FF-FF-FF-FF) is the broadcast address. All devices on the physical segment will see and respond to a message with that destination.
The offspring from an FF X ff cross will all have the genotype Ff.This is because they receive one allele from each parent, and in this case they can only receive an F from the FF parent and an f from the ff parent.
ff ff ff
There only certain crosses that will produce heterozygous offspring. These are heterozygous vs heterozygous, homozygous vs homozygous and heterozygous vs homozygous.