22.24 g hf
1 mole N2 = 28.0134g 1 mole N2 = 6.022 x 1023 molecules N2 28.0134g N2 = 6.022 x 1023 molecules N2 (4.00 x 1023 molecules N2) x (28.0134g/6.022 x 1023 molecules) = 18.6g N2
1 mol is equal to 6.02214179(30)×1023 molecules of the substance. The molecular weight is how much grams these molecules (6.02214179(30)×1023) weigh. Meaning g/mol.
What is the weight in grams of 3.36 × 1023 molecules of copper sulfate (CuSO4)?
Avogadro's Number = Avogadro's number = 6.0221415 × 10236.02×1023 (abbreviated); this is the number of atoms, ions, molecules, or anything else in 1 mole. 0.33 moles of water would have 0.33·6.02×1023 = 1.99×1023 molecules. However water's formula is H2O, so it has 3 atoms per molecule. (0.33 moles) × (6.02×1023 molecules per mole) = 1.99×1023 molecules.1.99×1023 molecules × 3 atoms per molecule = 5.96×1023 atoms(0.33 moles) × (6.0221415 × 1023molecules per mole) = 1.987306695×1023 molecules.1.987306695×1023 molecules × 3 atoms per molecule =5.961920085 1023 atomsI would use the rounded answer, 5.96×1023 atoms
The molar mass of O2 is 32 g/mol. To find the number of molecules in 48.0 grams of O2, we first need to find the number of moles using the formula: number of moles = mass / molar mass. Then, we can use Avogadro's number (6.022 x 10^23 molecules/mol) to convert moles to molecules.
1 mole H2O = 18.015g H2O = 6.022 x 1023 molecules H2O 1.5 x 1023 molecules H2O x 18.015g H2O/6.022 x 1023 molecules H2O = 4.5g H2O
To find the mass of 4.80 x 10^23 formula units of iron III nitrate, first calculate the molar mass of Fe(NO3)3. Then, multiply the molar mass by Avogadro's number to convert from formula units to grams. The mass will be 4.80 x 10^23 multiplied by the molar mass of iron III nitrate.
divide the amount of particles given in the question by avagado's number to get the amount in moles. 3.01 x 1023 / 6.022 x 1023 which is about 0.5 moles. them multiply the amount of moles by the mass of Nitrogen to get it in grams. 0.5 x 14 = 7g
The molar mass of water is approximately 18 grams/mol. So, one water molecule has a mass of 18/6.022 x 10^23 grams. Therefore, the mass of 1.5 x 10^23 water molecules would be 18 x 1.5 x 10^23/6.022 x 10^23 grams.
Gram mole is the mass of a substance which equal to molecular mass in amu. For ammonia we have one nitrogen atom and three atoms of hydrogen. So the molecular mass in amu will be 14+3 = 17 Now 17 g of ammonia would have 6.023 x 1023 molecules. ie avagadro number of molecules. Hence every 1 g will have (6.023/17) x 1023 So for 32 g it would have (32/17) x 6.023 x 1023 molecules.
In order to answer this question you need to know the molar mass of dinitrogen trisulfide (N2S3), and that 1 mole of molecules is equal to 6.022 x 1023 molecules. Molar mass is determined by multiplying each element's subscript by that element's atomic weight on the periodic table, and expressing it in grams/mole.1 mole N2S3 molecules = 6.022 x 1023 molecules N2S3molar mass N2S3 = 124.208g/molConvert molecules to moles.2.26 x 1025 molecules N2S3 x (1mol N2S3/6.022 x 1023 molecules N2S3) = 37.5 moles N2S3Convert moles to mass in grams.37.5mol N2S3 x (124.208g N2S3/1mol N2S3) = *4660 grams N2S3*The answer is rounded to three significant figures.
No, there will be more molecules in the 50 grams of NaCl, because its molacular weight is lower. NaCl has a molaculair mass of 58.44 g/mol and MgCl2 has a molcular mass of 95.21 g/mol. 50 g / 58.44 g/mol = 0.86 mol NaCl 50 g / 95.21 g/mol = 0.53 mol MgCl2 The avogadro contstant states that 1 mole equals 6.02214179*1023 molecules. So you have 0.86 * 6.022*1023 = 5.18*1023 molecules of NaCl and 0.53 * 6.022*1023 = 3.19*1023 molecules of MgCl2.