You need to know the cross sectional area of the pipe, this would be in square feet or square meters. Then take the volume flow in cubic feet per second, or cubic meters per second, and divide it by the area, this will give the velocity in ft/sec or m/sec
V=(21.22*Q)/D2
V = velocity
D= diameter of pipe
Q= flow
The Head just before entry to the pipe becomes velocity Head at the exit of the pipe. Assuming no losses: H=u^2/2g --> u=Square root of (2gH) where H is the height of the height of the level of water in the tank above the outlet of the pipe and u is the velocity. The velocity is such that if the water left the pipe vertically upwards and assuming no losses of any sort, the water would stop at the same level as the water in the tank. The volume flow rate is then uA where A is the area of the pipe, ie (πd^2)/4 Make sure you use the same units eg, u in meters per second, d and H in meters, g=9.81 m/s^2
The velocity is constant in a steady flow pipe while in the unsteady flow the velocity is not constant.
Maximum
The sound produced by a pipe is due to standing waves that are formed in the body of the pipe. The fundamental frequency,f1, produced, is given by the formula : f1=v/2L , where v is the velocity of the wave and depends only on the physical characteristics of the mean (e.g. air density), and L is the length of the pipe. So if the length increases the frequency decreases.
It's not a unit of measurement, that's for sure. It's a piece of equipment that measures the relative velocity of fluid, such as in wastewater applications or in firefighting (when you want to know how fast and hard the water is coming through a particular piece of pipe).
Velocity = PSI x 12.1 THEN 12.1 Sq.Example 65 PSI x 12.1 Sq - 28.04 FPS
Hello, Velocity in a pipe is the flow divided by the area. If the pipe is full, the area is simply pi*r². Here is a useful calulator for full pipes: http://www.tasonline.co.za/toolbox/pipe/velocity.htm
Static pressure is .434 X height Example 10 ft x .434 4.34 PSI to prove take 2.31 PSI x 4.34 To find FORCE to need to calculate the diameter of the piping and the height and then the weight of the water inside the pipe
it is useful to calculate branch in any degree:play.google.com/store/apps/details?id=com.nasirstore.branch
inside area of fluid conductor in centimeter square x velocity of fluid in centimeters per second/1000 = flow in litre per second simple formula: Q=a*v Q=Flow rate a=area of pipe v=velocity of fluid in the pipe
The Head just before entry to the pipe becomes velocity Head at the exit of the pipe. Assuming no losses: H=u^2/2g --> u=Square root of (2gH) where H is the height of the height of the level of water in the tank above the outlet of the pipe and u is the velocity. The velocity is such that if the water left the pipe vertically upwards and assuming no losses of any sort, the water would stop at the same level as the water in the tank. The volume flow rate is then uA where A is the area of the pipe, ie (πd^2)/4 Make sure you use the same units eg, u in meters per second, d and H in meters, g=9.81 m/s^2
Yes, it is actually one of the questions on a master plumbers exam
There isn't an answer to this question. Perhaps it needs to be re-phrased.
Depends on the internal diameter, and the flow velocity. Velocity of water = Delta V Internal Radius= R RxRxV= Volume
It's lacking the temperature of water to calculate its velocity having the pressure and the diameter of the pipe. The temperature of water also counts on this equation. The equation is valid for fresh water, if the density of the water is higher compared to the fresh water, the result will vary, too. It is lacking also the inner condition of the pipe. Smooth or rough. The pipe must be placed horizontally, 0º degree of inclination. The pipe must be fully straight, too.
yes
0.61 * d2 Where d is the diameter of the pipe in inches.