22.98977 grams.
4.2 teaspoons are present in 21 grams of cappucino
21 grams is about 0.740753201 ounces, or just a bit short of 3/4ths of an ounce. Here's the formula: 21 g* 1 oz 28.34952313 g = 0.7407532009 oz
0.2550 g AlC3 (1 mol/132 g) =0.001932 mol AlCl3 0.001932 mol AlCl3 (6.022 x 10^23 molecules AlCl3/1 mol AlCl3) = 1.163 x 10^21 1.163x10^21 molecules AlCl3 (3 mol Cl/1 mol AlCl3) =3.490x10^21 Cl ions 3.490x10^21 Cl ions (1 mol/6.022 x 10^23) =5.795x10^-3 moles Cl The formula to solve this problem appears above.
The amount of protons something has is equal to its atomic number. Sodium has 11 protons.
453.59 grams = 1 pound (rounded)0.021 gram = 0.0000463 pound (rounded)
4.828gNa X (1 mole/22.989gNa) = .21 22.989 = atomic weight of Na
1.56 X 10^21 atoms of sodium ( 1 mole Na/6.022 X 10^23) = 0.00259 moles sodium or 2.59 X 10^-3 moles sodium
How do you find the mass ratio. And how many grams fluorine is made at decomposition.
Sodium has an atomic mass of 29.990 g/mol. This means that 124 sodium atoms have a mass of 3718.76 amu, if the isotopes follow the average. To find in grams, the following must be used: 124 sodium atoms equal 2.0598 * 10-22 moles, so 124 sodium atoms have a mass of 6.177 *10-21 grams.
to get the answer just take number of moles you have and multiply it by the molecular mass of the compound which is 22g/mol in lithium oxide's case. 23mol x 22g/mol = 506 g of Li2O
Balanced equation first. 2Na + Cl2 -> 2NaCl 35 grams NaCl (1 mole NaCl/58.44 grams )( 1 mole Cl2/2 mole NaCl )( 70.9 grams Cl2/1 mole Cl2) = 21 grams of Cl2 needed
21 ounces = 595.34 grams.
1 gram = 10 decigrams so 21 grams = 21*10 = 210 grams. Simple!
21 ounces = 595.34 grams.
See the Related Questions to the left to solve this problem.
If the reaction were 2AlCl3 + 3Pb ---> 3PbCl2 + 2Al, then from this balanced equation, 14 moles of AlCl3 would produce 3/2 x 14 moles of PbCl2 = 21 moles of PbCl2.
4.2 teaspoons are present in 21 grams of cappucino