0.2550 g AlC3 (1 mol/132 g) =0.001932 mol AlCl3
0.001932 mol AlCl3 (6.022 x 10^23 molecules AlCl3/1 mol AlCl3) = 1.163 x 10^21
1.163x10^21 molecules AlCl3 (3 mol Cl/1 mol AlCl3) =3.490x10^21 Cl ions
3.490x10^21 Cl ions (1 mol/6.022 x 10^23) =5.795x10^-3 moles Cl
The formula to solve this problem appears above.
This reaction emmits H2 gas. We need 7.2 moles of Hcl.
The answer is 7, moles HCl.
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
The mass of sulfuric acid is 490,395 grams.
The answer is 699 moles perchloric acid.
A lot of that hydrochloric acrid is excess and some grams will not react, I think. Balanced equation first. Zn + 2HCl -> ZnCl2 + H2 Check to make sure of limiting reactant; I suspect zinc. 1.80 moles Zn (2 mole HCl/1 mole Zn) = 3.60 moles HCl You have a lot more than that, Zn limits and will drive the reaction 1.80 moles Zn (2 moles HCl/1 mole Zn)(36.458 grams/1 mole HCl) = 131 grams of hydrochloric acid reacted with that Zinc amount ----------------------------------------------------------------------------------
2 moles H2SO4 (98.086 grams/1 mole H2SO4)= 196.172 grams of sulfuric acid====================
44.1-44.5 -Apex
Aluminum.
No it wold not because Gallium is in the same family as Aluminum and therefore has similar properties to Aluminum. Aluminum does not react with acetic acid.
12 moles Li
Hydrochloric acid will react with Aluminum to form Aluminum Chloride (AlCl3) but not with Nickel.
0.1538 grams
4 moles HNO3 (63.018 grams/1 mole HNO3) = 252 grams nitric acid ================
I think you meant " How many moles of acetic acid in 25 grams of acetic acid? " We will use the chemist formula for acetic acid, 25 grams C2H4O2 (1 mole C2H4O2/60.052 grams) = 0.42 mole acetic acid =================
FeS+2HCl-->FeCl2+H2S Moles of H2S produced equal to moles of FeS used. Moles of H2S=12\34=0.353mol Grams of Fes=0.353*88=31.05g
The mass of sulfuric acid is 490,395 grams.
C2H4O2 Find moles first. Molarity = moles of solute/Liters of solution moles C2H4O2 = molarity/Liters solution moles C2H4O2 = 0.1 M/10 L = 0.01 moles C2H4O2 -----------------------------------now, molar mass time moles 0.01 moles C2H4O2 (60.052 grams/1 mole C2H4O2) = 0.60 grams acetic acid needed --------------------------------------------
This reaction?2Al + 6HCl -> 2AlCl3 + 3H2Get moles species.60.0 grams Al (1 mole Al/26.98 grams) = 2.2239 mole Al==================================================================================2.2239 moles Al (6 mole HCl/2 mole Al)= 6.6717 moles HCl-------------------------0.68572 moles HCl (2 mole Al/6 mole HCl)= 0.22857 mole Al------------------------As you see you have way more moles aluminum than you need, but. you do not have nearly enough HCl to meet the mole burden.Hydrochloric acid limits this reaction.