99
92.4 grams
I think 92.4 grams
92.4- Nova Net
To calculate the grams of CO2 in 14 mol of the compound, first find the molar mass of CO2: 1 carbon atom (12.01 g/mol) + 2 oxygen atoms (16.00 g/mol each) = 44.01 g/mol. Next, multiply the molar mass of CO2 by the number of moles given (14 mol): 44.01 g/mol x 14 mol = 616.14 grams of CO2.
CaC12
To find the number of moles in 6.5 grams of CO2, you first need to calculate the molar mass of CO2, which is 44.01 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 6.5 grams / 44.01 g/mol = 0.148 moles of CO2.
This depends on the chemical compound.
The balanced equation is: 2C + O2 -> 2CO2. First, determine the moles of C and O2: 4g C / 12 g/mol = 0.33 mol C and 10.67g O2 / 32 g/mol = 0.33 mol O2. From the balanced equation, 2 moles of C produces 2 moles of CO2, so 0.33 mol C will produce 0.33 mol CO2. Since CO2 has a molar mass of 44 g/mol, the total grams of CO2 produced will be: 0.33 mol CO2 x 44 g/mol = 14.52 grams of CO2.
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
The molar mass of LiOH is 23.95 g/mol for lithium, 15.999 g/mol for oxygen, and 1.008 g/mol for hydrogen, totaling 41.943 g/mol for LiOH. This means that for every 41.943 grams of LiOH, 44.01 grams of CO2 can be absorbed. To find out how much CO2 can be absorbed by 580.0 grams of LiOH, you can set up a simple ratio and cross-multiply to get your answer.
The molecular formula of amyl alcohol is C5H12O. When burned, it reacts with oxygen to form carbon dioxide and water. The balanced equation is: C5H12O + 8O2 → 5CO2 + 6H2O. From this equation, we can see that 1 mol of amyl alcohol will produce 5 mol of CO2. To calculate the grams of CO2 produced, we can use the molar mass of CO2 (44 g/mol) and the molar ratio from the balanced equation.
44 grams of CO2 (1 mol CO2 from 1 mol C if enough oxygen, air, is available)