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Q: How are even and odd addressed bytes accessed in 8086 memory address space?
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How many address lines will take to address the 16kilo bytes?

16KB, or 16384 bytes, can be addressed with 14 address lines. (214 = 16384)


How many bytes of memory on a 128MB computer?

The memory is to be designed so that 16-bitdata can be accessed in one .Two 64K X 8 SRAM chips have a capacity of 128KB.


If a memory had 16 bit address bus and a 32 bit data bus what is the largest size of the memory?

A memory with a 16 bit address bus can address 216 or 65536 distinct items. If each item is 32 bits in size, then the item is 4 bytes. The size of this memory is then 262144 bytes. (256Kb)


A computer has 64MB megabytes of memory Each word is 4 bytes How many bits are needed to address each single word in memory?

The memory address space is 64 MB, which means 226. However, each word is 4 bytes, which means that you have 224 words. This means you need log2 224 or 24 bits, to address each word.


Maximum memory address space that the processor can access directly if it is connected to a 16-bit memory?

Max. memory address space= 216 X 2 bytes = 128 Kbytes


What is the address of the last byte of RAM in the Pep8 memory?

2 bytes or 16 bits


How many memory address does this number of address lines allow the 8086 to access directly?

The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.


What is the What is the maximum memory address space that the processor can access directly if it is connected to a 8 bit memory considering a hypothetical microprocessor generating a 8 bit address?

microprocessor can access 2^8 points which is 256 then we have 8 bit memory = 1 bytes then 1*256 =256 bytes


How many bytes does null occupy?

In most languages with a null reference, it is simply a memory address to a zero-length memory block. So the only memory it would occupy in these cases would be enough for a memory pointer: usually around 4 bytes.


Ram memory is measured in bytes how many bytes are there in 2gb of ram memory?

2147483648 bytes


What is aligned address?

A memory address a, is said to be n-byte aligned when a is a multiple of n bytes (where n is a power of 2). In this context a byte is the smallest unit of memory access, i.e. each memory address specifies a different byte.


How many memory addresses does this number of address lines allow the 8086 to access directly?

The 8086/8088 has 20 address lines. It can access 220, or 1MB, or 1,048,576 bytes of memory.