they enjoy making love to oxygen atoms
Boron will form the covalent bonds based on the octet rule.
No. Some molecules, such as boron triflouride (BF3) and phosphorus pendachloride (PCl5) are octect violators.
Sort of. Lithium loses one electron in order to achieve the noble gas configuration of helium, which has only two valence electrons in its 1s sublevel. The octet rule refers to the fact that atoms share or transfer electrons in order to achieve a noble gas configuration with eight valence electrons, called an octet. Helium is an exception to the rule.
Flourins has 2s2 and 2p5 configuration and total 9 electrons in outermost shell. There are two possibilities for fluorine i.e. either to complete the outermost shell or to follow the octet rule. If it follow the octet rule there will remain 4 electrons in 2p. Hence its reactivity towards metals or other compounds will differ which is against its nature.Thats why flourine shows restrictions towards octet rule
Yes. Magnesium gives up 2 electrons and goes down to a lower electron shell with a full octet. Each chlorine gains 1 electron from the magnesium to complete its octet.
Boron is one. It exceeds the octet rule.
Boron And Berylium
octet rule
Boron trichloride does not follow the octet rule. Boron does not allow the eight required electrons in the outer shell.
Hydrogen does not obey the octet rule. Boron does not always obey the octet rule and in fact forms Lewis acids such as BF3 which only has 6 electrons.
It does follow the octet rule!
Boron has two few valence electrons to ever obtain a full octet.
First, it helps to draw out the Lewis structure. Boron, being the least electronegative element is in the center, with the three Bromines singly bonded around it. Each Br has an octet of electrons (3 lone pairs plus the single bond) and there are no electrons left over to go onto the Boron. This leaves Boron without an octet, but Boron is an exception to the octet rule so that's okay. So, no BBr3 does not follow the octet rule.
Some elements that are known to violate the octet rule are: Hydrogen, Helium and Lithium (two electrons) Aluminum and Boron (less than octet but will form an octet if possible), Period 3 elements with p orbitals (more than an octet using empty d orbitals), noble gas compounds (more than an octet), and elements like nitrogen with an odd number of electrons (form free radicals when octets are not possible).
No it is not fully obeying the octet rule. Boron has only 6 electrons (3 own + 3 from each F atom), lacking two for the octet. Fluorine is 3x satisfied, each with 8 electrons (each has 7 own plus 1 from boron).
no it does not follow octet rule
Boron will form the covalent bonds based on the octet rule.