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let us consider three inputs a,b,c and their sum as s, difference as d and carry as c and borrow b

in full adder circuit :-

s= a (XOR) b (XOR) c

carry = ab+ac+bc

in full subtractor :-

d= a (XOR) b (XOR) c

borrow b = a'b+a'c+bc

so on observing these two we notice that sum and difference are one and the same coming to carry and borrow the only difference is to obtain borrow from carry just complement the input a

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11y ago
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6y ago

Id say look at a few YouTube videos that will help everythings on youtube

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10y ago

show how to convert full adder to full subtructer

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Q: How can convert a full adder to a full subtractor with circuit?
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simply by complementing x input before applying to and gate for generating carry


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