The molecule is described that way in order to give an idea of the bond pattern. If you just wanted to count elements, you could also call it C2H4O2 which gives the same count. But it has a pattern. There is a carbon in the middle, it has a methyl group (CH3) attached to it, and an oxygen attached to it, and a hydroxyl group (OH) attached to it. It has 3 different bonds, the oxygen is a double bond and the other two are single bonds, adding up to four, which is exactly the valence of carbon, so it works perfectly.
Methanol (CH3OH) can be oxidized to ethanoic acid (CH3COOH) using a strong oxidizing agent like potassium permanganate (KMnO4) in acidic conditions. The chemical equation for this reaction is: 2 CH3OH + 2 [O] → 2 CH3COOH + 2 H2O Here, [O] represents the oxygen atoms from the oxidizing agent.
The abbreviation for Acetate is CH3COOH. This is an organic acid.
Since H6 = +1 x6 = +6 and O= -2 . You are left with +4, therefore each C atom has -2
What is the balanced equation for Ch3COOH alone
well, 5% acetic acid has an elemental makeup of C(2)H(4)O(2)
Remember the equation moles = mass(g) / Mr The Mr ( Relative molecular mass) for ethanoic (acetic) acid is CH2COOH C x 2 = 12 x 2 = 24 H x 4 = 1 x 4 = 4 O x 2 = 16 x 2 = 32 24 + 4 + 32 = 60 ( The Mr ( Ethanoic acid) ) Substituting moles = 458.77 g / 60 = 7.6461666.... moles moles ~ 7.65 ( 2 d.p.)
The conjugate base of CH3COOH is CH3COO-. This forms when CH3COOH loses a proton (H+).
The reaction between zinc oxide (ZnO) and acetic acid (CH3COOH) results in the formation of zinc acetate and water. The balanced chemical equation for this reaction is: ZnO + 2CH3COOH -> Zn(CH3COO)2 + H2O
carbon oxygen hydrogen = CH3COOH is the thingy for vinegar
Acetic Acid, CH3COOH, has a molecular weight of 60.05
The balanced chemical equation for the combustion of acetic acid (CH3COOH) is: 2 CH3COOH + 4 O2 → 4 CO2 + 4 H2O
Ethanoic (Acetic) Acid formula is CH3COOH This formula tells us that it contains ;=- 2 x C = Two Carbons 4 X H =(3+1) = Four Hydrogens 2 x O = Two Oxygens. 2 + 4 + 2 = 8 So one molecule of ethanoic acid contains 8(eight) atoms.