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Remember the equation
moles = mass(g) / Mr
The Mr ( Relative molecular mass) for ethanoic (acetic) acid is
CH2COOH
C x 2 = 12 x 2 = 24
H x 4 = 1 x 4 = 4
O x 2 = 16 x 2 = 32
24 + 4 + 32 = 60 ( The Mr ( Ethanoic acid) )
Substituting
moles = 458.77 g / 60 = 7.6461666.... moles
moles ~ 7.65 ( 2 d.p.)
What else can I help you with?
How many moles are in 978 g Ca?
978 g calcium contain 24,4 moles.
How many moles are in 29.0 g of calcium?
29,0 g of calcium is equal to 0,723 moles.
How many moles are in 67.4 g of HCI?
67,4 g HCl is equivalent to 1,85 moles.
How many moles are in 14.84 g Mg?
14,84 g magnesium are equivalent to 0,61 moles.
How many moles are in 97.5 g of oxygen?
97,5 g of oxygen is equal to 5,416 moles.
How many moles of acetic acid are contained within 24.71g of acetic acid?
To find the number of moles, we first need to calculate the molar mass of acetic acid (CH3COOH). The molar mass is 60.05 g/mol. Next, we can use the formula: number of moles = mass / molar mass number of moles = 24.71g / 60.05 g/mol This gives us approximately 0.41 moles of acetic acid.
If you have g of beryllium how many moles is this equivalent to?
The formula is: number of moles = g Be/9,012.
How many moles are in 14.84 g Mg?
14,84 g magnesium are equivalent to 0,61 moles.
How many moles are in 97.5 g of oxygen?
97,5 g of oxygen is equal to 5,416 moles.
How many moles are in 978 g Ca?
978 g calcium contain 24,4 moles.
How many moles is 573.28 g of AgCI?
573,28 of g of AgCI is equivalent to 4 moles.
How many moles are in 67.4 g of HCI?
67,4 g HCl is equivalent to 1,85 moles.
How many moles are in 29.0 g of calcium?
29,0 g of calcium is equal to 0,723 moles.
How many moles are in 27.4 g of water?
27.4 g H2O x 1 mole/18 g = 1.52 moles
Calculate the number of grams of CH3COOH in the vinegar?
depends of the mass volume and concentration of ethanoic acid for example 100ml, and a concentration of 1 mole/l moles = concentration*volume moles = 1*100/1000 (remeber volume is in litres) therefore there is 0.1 moles mass = moles*gfm gfm = 2*12 + 2*16 + 4 = 44 hence mass = 4.4grams
How many moles of Ca are in 156 g of the element?
156 g calcium is equivalent to 3,89 moles.
How many moles of Fe2O3 are in 231 g of the compound?
231 g of Fe2O3 are equal to 0,69 moles.
