depends of the mass volume and concentration of ethanoic acid
for example 100ml, and a concentration of 1 mole/l
moles = concentration*volume
moles = 1*100/1000 (remeber volume is in litres)
therefore there is 0.1 moles
mass = moles*gfm
gfm = 2*12 + 2*16 + 4 = 44
hence mass = 4.4grams
Acetic Acid, CH3COOH, has a molecular weight of 60.05
The mass number is the total number of protons and neutrons in an atom's nucleus. To calculate the mass number, simply add the number of protons and neutrons together in the nucleus of an atom.
To find the percent by weight of CH3CO2H in vinegar, you need to know the molar mass of CH3CO2H and the density of vinegar. Once you have that information, you can calculate the weight of CH3CO2H in a given volume of vinegar, and then express that weight as a percentage of the total weight of the solution.
To convert the number of molecules to grams, first calculate the molar mass of N2O6. The molar mass of N2O6 is 92.02 g/mol. Then use this value to convert the number of molecules to grams using the formula: ( \text{Grams} = \frac{\text{Number of molecules}}{6.022 \times 10^{23}} \times \text{Molar mass} ) Calculate: ( Grams = \frac{8.281023}{6.022 \times 10^{23}} \times 92.02 )
The molar mass of acetic acid is 60,05 g.
Molarity = moles of solute/liters of solution 1/10^pH = Molarity ( or 10^ - pH ) = 1 X 10^-4 M ---------------------- find moles CH3COOH moles of solute = 1 X 10^-4 M/3.4 liters = 2.94 X 10^-5 moles CH3COOH (60.052 grams/1 mole CH3COOH) = 0.0018 grams CH3COOH needed ------------------------------------------------- ( 1.8 X 10^- 3 grams )
Acetic Acid, CH3COOH, has a molecular weight of 60.05
There are 59.5 mmols of baking soda and 167 mmols of vinegar. The reaction of the two substances is NaHCO3(s) + CH3COOH(l) = CO2(g) + H2O(l) + Na+(aq) + CH3COO-(aq). This means the limiting reactant is baking soda, and 2.62 grams of CO2 is produced.
A 5.54 gram sample of vinegar was neutralized by 30.10 mL of 0.100 M NaOH. What is the mass percent by weight of acetic acid in the vinegar?Given Calculations 1) Total Vinegar (CH3COOH solution) mass: 5.54 grams.2) Neutralizing Sodium Hydroxide (NaOH): 30.10 mL (0.03010 Liters).(Step 1)Find the molar mass of CH3COOH(C2 = 24.02) + (H4 = 4.032) + (O2 = 31.998) = 60.05 grams (molar mass)(Step 2)Find the moles of NaOHMoles of NaOH = (0.100 M NaOH) x (0.03010 Liters NaOH) = 3.01 x 10-3 moles(Step 3)Find the grams of CH3COOHGrams of NaOH = 3.01 x 10-3 x 60.05 (molar mass) = 0.18075 grams(Grams of CH3COOH = Grams of NaOH at equivalence point, the point where the solution was neutralized)(Step 4)Find mass percent of Acetic Acid in VinegarMass % = (0.18075 grams CH3COOH / 5.54 grams vinegar) x 100 = 3.26%
About 15 grams, same as water. But vinegar is easier to measure by volume in a tablespoon or in glassware such as a graduated cylinder than by mass on a balance. I doubt you'll find a recipe that requiring vinegar that specifies a certain number of grams. Millilitres, perhaps.
The mass number is the total number of protons and neutrons in an atom's nucleus. To calculate the mass number, simply add the number of protons and neutrons together in the nucleus of an atom.
Which type of vinegar? at what temperature and pressure... ? What is the volume of a cup? Without knowing the specifics I guess about 23.
To find the percent by weight of CH3CO2H in vinegar, you need to know the molar mass of CH3CO2H and the density of vinegar. Once you have that information, you can calculate the weight of CH3CO2H in a given volume of vinegar, and then express that weight as a percentage of the total weight of the solution.
yes, vinegar has a density of 1.01 grams per milliliter whereas water is 1.00 grams per milliter
Divide that number by the number of grams which the cake weighs.
For this you need the atomic (molecular) mass of CH4O. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CH4O=32.0 grams.998 grams CH4O / (32.0 grams) =.0312 moles CH4O
To calculate the number of grams in 4.1 x 10^22 molecules of N2I6, you first need to find the molar mass of N2I6. Then, use this molar mass to convert the number of molecules to grams using Avogadro's number and the formula: grams = (number of molecules) / (Avogadro's number) * molar mass.