their colours, a white precipitate for silver chloride, and a yellow precipitate for silver iodine
Reddish precipitate of Mercuric iodide and clear solution of Potassium chloride is produced
Bromide: Ag+ + Br- = AgBr which is a cream precipitate Chloride: Ag+ + Cl- = Ag Cl which is a white precipitate Iodide: Ag+ + I- = AgI which is a yellow precipitate
Chloride anions form a white precipitate of silver chloride when mixed in solution with silver nitrate.
The equation for this reaction that creates insoluble silver chloride is:NaCl + AgNO3 = NaNO3 + AgClThat's the right equation, but not net ionic. I got it marked wrong for basically the same question except the salt was MgCl2
to remove part of water in the precipitate
Chloride and iodide ions can be distinguished by the colour of their precipitate which are formed by treatig it with silver nitrate solution.
Reddish precipitate of Mercuric iodide and clear solution of Potassium chloride is produced
Lead(ii) Iodide is a yellow precipitate while silver chloride is white.
The precipitate would be calcium carbonate, CaCO3.
Bromide: Ag+ + Br- = AgBr which is a cream precipitate Chloride: Ag+ + Cl- = Ag Cl which is a white precipitate Iodide: Ag+ + I- = AgI which is a yellow precipitate
Chloride anions form a white precipitate of silver chloride when mixed in solution with silver nitrate.
Take a few drops of both samples and add some lead nitrate. A yellow precipitate indicates lead iodide and it gives the inference that it contains iodide ions, hence the solution of sodium iodide.
A yellow Lead(II) iodide precipitate
The equation for this reaction that creates insoluble silver chloride is:NaCl + AgNO3 = NaNO3 + AgClThat's the right equation, but not net ionic. I got it marked wrong for basically the same question except the salt was MgCl2
Yes it is a precipitate, generally yellow in colour
to remove part of water in the precipitate
If you add iodide (iodine ions) to Acidfied Silver Nitrate, a pale yellow precipitate is formed. This precipitate is Silver Iodide (AgI).