their colours, a white precipitate for silver chloride, and a yellow precipitate for silver iodine
When mercuric chloride is mixed with potassium iodide, a white precipitate of mercuric iodide is formed. This reaction is a double displacement reaction where the ions in the two compounds switch partners. Mercury(II) chloride is soluble in water, while potassium iodide is also soluble, so their reaction forms the insoluble mercuric iodide precipitate.
Chloride anions form a white precipitate of silver chloride when mixed in solution with silver nitrate.
The ionic equation between halides and silver nitrate involves the cation from silver nitrate combining with the anion from the halide compound to form a precipitate. For example, with chloride ions, Ag^+ from silver nitrate reacts with Cl^- from the chloride compound to form solid silver chloride (AgCl) precipitate. The net ionic equation would show the formation of the silver halide precipitate.
Silver chloride (AgCl) gives a white precipitate. Silver Bromide (AgBr) also gives a white precipitate, though it's a slightly more creamy white than the precipitate formed by AgCl. Silver iodide (AgI) gives a pale yellow precipitate.
The equation for this reaction that creates insoluble silver chloride is:NaCl + AgNO3 = NaNO3 + AgClThat's the right equation, but not net ionic. I got it marked wrong for basically the same question except the salt was MgCl2
One way to distinguish between sodium chloride and sodium iodide is through a simple taste test. Sodium chloride (table salt) will taste salty, while sodium iodide will have a slightly sweet and salty taste. Another method is to perform a chemical test by adding a few drops of dilute sulfuric acid; sodium chloride will produce a white precipitate, while sodium iodide will produce a yellow precipitate.
When mercuric chloride is mixed with potassium iodide, a white precipitate of mercuric iodide is formed. This reaction is a double displacement reaction where the ions in the two compounds switch partners. Mercury(II) chloride is soluble in water, while potassium iodide is also soluble, so their reaction forms the insoluble mercuric iodide precipitate.
You can distinguish between Cl and I by using chemical tests, such as the silver nitrate test. Chlorine (Cl) forms a white precipitate with silver nitrate, while iodine (I) forms a yellow precipitate. Additionally, you can use other methods such as spectroscopy or flame tests to identify the elements.
Some examples of simple precipitation reactions include mixing silver nitrate with sodium chloride to form silver chloride precipitate, mixing lead nitrate with potassium iodide to form lead iodide precipitate, and mixing barium chloride with sodium sulfate to form barium sulfate precipitate.
Chloride anions form a white precipitate of silver chloride when mixed in solution with silver nitrate.
The precipitate produced by the reaction between calcium chloride and potassium carbonate is calcium carbonate. When calcium chloride and potassium carbonate are mixed together, a double displacement reaction occurs, leading to the formation of calcium carbonate, which is insoluble and thus precipitates out of the solution.
The ionic equation between halides and silver nitrate involves the cation from silver nitrate combining with the anion from the halide compound to form a precipitate. For example, with chloride ions, Ag^+ from silver nitrate reacts with Cl^- from the chloride compound to form solid silver chloride (AgCl) precipitate. The net ionic equation would show the formation of the silver halide precipitate.
Yes it is a precipitate, generally yellow in colour
Take a few drops of both samples and add some lead nitrate. A yellow precipitate indicates lead iodide and it gives the inference that it contains iodide ions, hence the solution of sodium iodide.
Lead iodide (PbI2) is a compound consisting of lead and iodine, whereas silver chloride (AgCl) is a compound made up of silver and chlorine. Lead iodide is yellow in color and is more soluble in water compared to silver chloride, which is white in color and has low solubility in water. Lead iodide has different chemical and physical properties compared to silver chloride, due to the different elements it contains.
Silver chloride (AgCl) gives a white precipitate. Silver Bromide (AgBr) also gives a white precipitate, though it's a slightly more creamy white than the precipitate formed by AgCl. Silver iodide (AgI) gives a pale yellow precipitate.
The equation for this reaction that creates insoluble silver chloride is:NaCl + AgNO3 = NaNO3 + AgClThat's the right equation, but not net ionic. I got it marked wrong for basically the same question except the salt was MgCl2