If you mean the appliance has a 4 in. vent and you are trying to go to a 6 in. vent then yes you can but is it safe? It can be but you need to be sure. If the flue gas cools to much in the larger pipe then, first the water vapor (which is acidic) will condensate, then if the gas cools enough it will fall back down the pipe which will fill your house with poison gas (carbon monoxide). The other way, going from a 6 in. appliance vent to a 4 in. flue pipe is illegal because of the back pressure. Again this is a sure fire way to kill your family.
Read all you can and talk to people that make vent pipe. Just do an internet search for "type b" vent pipe.
Another thing, buy a carbon monoxide monitor. The cost is less then $50 for a good one and it could very well save your families life.
where one toilet is draining to its own unshared line, the line can be 3" but once both toilets are draining to the same line, it needs to be 4". in other words, from the first toilet to the second toilet can be 3" but past the second toilet needs to be 4". there needs to be a vent downstream of the second toilet in the direction of flow if there is another fixture of any kind downstream of the two toilets.
1. GunPowder 2. Papermaking 3. Compass 4. Printing (Woodblock and movable type) 5. Chopsticks
1- inadequate water pressure 2- Poor venting 3- Undersized waste / vent lines 4- Not enough volume in the tank 5- Partial stoppage 6- Not enough pitch 7- Wrong piston / diaphragm installed in Flushometer A combination of all of the above
Simply put, absolute spread in a rolling mill is the difference in the width of the stock we put in and the width of the finished piece. For instance, if a bar goes in and is rolled to reduce its thickness and it is 4 inches wide when it goes in and is 10 inches wide when it comes out, the absolute spread of the rolling mill in this operation is 6 inches. (The maximum output width, 10 inches, minus the input width, 4 inches, equals the absolute spread, 6 inches.)
Let us consider a tor steel of diameter 'd' mm and length 1 m d mm=d*10^-6 m Area of cross section,A=(3.14*d^2*10^-6)/4 Volume of steel bar of length 1 m=((3.14*d^2*10^-6)/4)*1 m Sp.Weight of steel=7850 kg/m3 so,Weight of tor steel=((3.14*d^2*10^-6)/4)*7850 Kg Hence 162 is nothing but a constant used for calculating weight of all type of tor steel and it is found out from; (4*10^6)/(3.14*7850)=162
6/8 = 3/4
To 1/4
3over 2
4/6 = 2/3
4/12 = 2/6 = 1/3
5/6 - 1/6 (5 - 1) / 6 = 4/6 Since 4/6 is an equivalent fraction, reduce to its lowest terms. 4/6 = 2/3
4/12 = 2/6 = 1/3
6√20 First we reduce the 6 and 3 so we get 2√20 Then we reduce the 20 and 53√5 `````````````````````````````````√5so we get 2√4 We know that √4 is 2 so by substituting, we get 2x2 which is 4.
6
The Type S DH-10081-6 Vent Drink Holder is the best car cupholder and is the bestselling as well.
8 and 6 are both divisible by two, so we reduce 8/6 = 4/3. 4 and 3 don't share any factors, so 4/3 is as far as we can reduce this fraction. 4/3 = 1 1/3 = 1.33...
In order to reduce any fraction to its lowest terms, divide both the numerator and denominator by their greatest common factor.