For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the Atomic Mass. Multiply by one mole for units to cancel. CO2=44.0 grams
33.0 grams C / (44.0 grams) = .750 moles CO2
There are 2.0 moles in 32 grams of methane.
The molecular mass of CO2 is 12.0 + 2(16.0) = 44.0
Amount of CO2 in 30.0g sample = 30.0/44.0 = 0.682mol
Depends on how many moles of one substance, as well as its gram atomic/formula/molecular mass.
No. of moles= Given mass of substance/Molar mass of substance.
No. of moles of carbon dioxide in 33 grams= 33/44=0.75 moles
The answer is 1,665 (73,3/44,01); 44,01 is the molecular mass of carbon dioxide.
1.33 (g CO2) / 44 (g/mol CO2) = 0.030 mol CO2 = 0.030 mol O2
1 mole CO2 = 44.009g CO2 = 6.022 x 1023 molecules CO2
33.6g CO2 x 6.022 x 1023 molecules CO2/44.009g CO2 = 4.60 x 1023 molecules CO2
One molecule of CO2 has one carbon atom and two oxygen toms. denoted by the formula CO2 So in two molecules of CO2 there are CO2 & another CO2 . Chemically this is shown as 2CO2, that is a figure is placed to the left of the molecular formula. Since there are CO2 & another CO2 , then there are two(2) atoms of carbon and four(4) atoms of oxygen.
We know for every 6.022 x 10^23 molecules, we have a mole of a substance, right? So if we have 3920molecules, we can use the above conversion factor to get: 3920 molecules CO2 x (1mol CO2/(6.022x10^23molecules CO2)) = 6.51 x 10^-21 moles CO2. There are three significant figures in this problem, from the 3929 molecules.
Carbon Dioxide-CO2 To get molecules, we must convert grams to moles and moles to atoms using Avogadro's number. Molar mass of CO2= C:12.0g+O:16.0gx2=44.0g CO2 25.0g CO2 | 1 mol CO2 | 6.02x10 23 molecules CO2 ------------------------------------------------------------------- = 3.42x10 23 molecules CO2 1 | 44.0g CO2 | 1 mol CO2 Now to get the number of oxygen atoms. Since there are 3 atoms in CO2 and 2 of them are oxygen, we will divide by 3 (1.14x10 23) and multiply by 2 (2.28 x10 23) So the number of oxygen atoms in 25.0 grams of CO2 is 2.28x10 23 or 228 000 000 000 000 000 000 000
CO2 is called Carbon Dioxide because it has 2 Oxygen molecules.
== == Technically speaking, three turns of the Calvin cycle produce one Glyceraldehyde-3-phosphate (G3P). Each turn of the Calvin Cycle uses 1 CO2. So three CO2 (3 cycles) for 1 G3P. Since 2 G3P are needed for 1 molecule of glucose = six molecules of CO2. As a side note, for one molecule of glucose= requires 6 CO2 + 18 molecules of ATP + 12 molecules of NADPH. (Source: Campbell and Reece, 2005)
8.066
2.65 mol * 64.07 g/mol = 169.79 g
The number of molecules is 0,90332112855.10e23.
The balanced equation for the combustion of CH4 is CH4 + 2O2 ==> CO2 + 2H2O4 molecules of CH4 will produce 4 molecules of CO2 and 8 molecules of H2O
the answer is 2!
1 mole CO2 = 6.022 x 1023 molecules 2.4mol CO2 x 6.022 x 1023 molecules CO2/1mol CO2 = 1.4 x 1024 molecules CO2
my Glizzy
Each mole of C2H6O will have 6.022 E23 molecules present. That means that in 3.25 moles, there are 1.957 E24 molecules present.
2.75 x 1024molecules of CO2
The number is zero.No CO2 is produced in glycolisis.
The number of molecules is 7,52767607125.10e23.
6 CO2 + 6 H2O →C6H12O6 + 6 O2Carbon dioxide + Water + Light energy → Glucose + Oxygen6 molecules of CO2