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How to calculate a parallel circuit with more than one load in its branches?
If a 'parallel' circuit has more than one load in its (not "it's"!) branches, then it is not a parallel circuit, but a series-parallel circuit! To resolve the circuit, you must first resolve the total resistance of the loads within each branch.
Why you take the conjugate of current in complex power?
In order to calculate the complex power of a circuit, the conjugate of current is used. The Vrms of the circuit is multiplied by the complex conjugate of the total circuit current.
4 How do you determine current in a parallel DC circuit?
The current in each individual component of the parallel circuit is equal to (voltage across the combined group of parallel components) / (individual component's resistance). The total current is the sum of the individual currents. ============================== Another approach is to first calculate the combined effective resistance of the group of parallel components. -- take the reciprocal of each individual resistance -- add all the reciprocals -- the combined effective resistance is the reciprocal of the sum. Then, the total current through the parallel circuit is (voltage across the parallel circuit) / (combined effective resistance of the components).
How do you calculate total power in parallel?
Either (1) determine the power of each branch, and add them together, or (2) multiply the load current by the supply voltage.
In a parallel circuit adding more bulbs will increase?
It will decrease the effective load resistance across the power supply terminals, increase the total current through the load, and increase the total power required to be supplied by the power supply.
In a parallel circuit does the power of each branch add up?
Yes, the total power dissipated through the circuit is equal to the sum of the power of each branch in a parallel circuit.
Why is the total power equals the sum of the individual values of power in a series circuit or a parallel circuit is used?
The total power equals the sum of the individual powers because power is the rate at which energy is supplied. Whether you have a series or parallel circuit, the total power comes from the power source.
How to calculate a parallel circuit with more than one load in its branches?
If a 'parallel' circuit has more than one load in its (not "it's"!) branches, then it is not a parallel circuit, but a series-parallel circuit! To resolve the circuit, you must first resolve the total resistance of the loads within each branch.
Why you take the conjugate of current in complex power?
In order to calculate the complex power of a circuit, the conjugate of current is used. The Vrms of the circuit is multiplied by the complex conjugate of the total circuit current.
When you have watts in a series circuit do you add up the total or is it the reciprocal?
The power dissipated by the complete circuit, no matter whether it's a series or parallel one, is the simple sum of the power dissipated by each component of the circuit.
What is the relationship between the total power supplied and the power consumed by the individual resistors in a parallel circuit?
power supplied=sum of powers delivered to individual elements
Is the power dissipated in a parallel circuit larger than the power dissipated in a serial circuit?
Consider t resistors with same Ohmic values. If they are in series total resistance Rt = R1 + R2. if they are in parallel then total resistance Rt = 1/R1 + 1/R2. Series connection will have higher resistance.
Is the sum of the resistance in a parallel circuit always excessds the total resistance in a circuit?
Not sure what you mean. The equivalent (total) resistance in a parallel circuit is less than any individual resistance.
4 How do you determine current in a parallel DC circuit?
The current in each individual component of the parallel circuit is equal to (voltage across the combined group of parallel components) / (individual component's resistance). The total current is the sum of the individual currents. ============================== Another approach is to first calculate the combined effective resistance of the group of parallel components. -- take the reciprocal of each individual resistance -- add all the reciprocals -- the combined effective resistance is the reciprocal of the sum. Then, the total current through the parallel circuit is (voltage across the parallel circuit) / (combined effective resistance of the components).
How do you calculate the total mA needed to power 3 9v DC 200 mA devices?
Separate devices should always be hooked up in parallel, and not series. Therefore, you would combine the total current requirement, which in this case is 600mA or 0.6A. You would therefore need a 9V power supply that is capable supplying at least 0.6A. It depends on whether the devices are connected in series or parallel or some combination of the two. The current in a series circuit is the same throughout the circuit. The current in a parallel circuit is the sum of the current in each parallel branch If the three devices are connected in series, the required current is 200mA. If the three devices are connected in parallel, the required current is 600mA The total power required by a circuit is the sum of the power consumed by each component. It doesn't matter if the devices are connected in series or parallel. Power = voltage x current. If the three devices are in series, the power consumed by one of them is 9 x .2 = 1.8 watts. The total power consumed is 1.8 x 3 = 5.4W If the three devices are connected in parallel, the power consumed is 9 x .6 = 5.4W Notice that the power consumed is the same for the series and parallel combination. The battery (or power supply) must be able to supply 5.4 watts.
Is series parallel the same as parallel?
No, series parallel, as it implies has components of the circuit configured in both series and parallel. This is typically done to achieve a desired resistance in the circuit. A parallel circuit is a circuit that only has the components hooked in parallel, which would result in a lower total resistance in the circuit than if the components were hooked up in a series parallel configuration.
In a parallel circuit each resistor?
reduces the total resiostance
