CI2+KI=2KCI+I2
Pb(No3)2(aq) + KI(aq) --> PbI2(s) + KNO3(aq) aq = aqueous s = solid Lead iodide is a yellow precipitate!
2 ci + 2 ki = 2 kci + i2
Already balanced
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3
CI2+KI=2KCI+I2
Pb(No3)2(aq) + KI(aq) --> PbI2(s) + KNO3(aq) aq = aqueous s = solid Lead iodide is a yellow precipitate!
2 ci + 2 ki = 2 kci + i2
Already balanced
Potassium iodide and lead nitrate produces lead iodide and potassium nitrate its a Precipitation Reactions. 2KI+Pb(NO3)2-->PbI2 + 2KNO3
Pb(NO3)2 + 2KI ==> PbI2 + 2KNO3
KI + NaCl = KCl + NaI
The reaction is the following:AgNO3 + KI = KNO3 = AgI(s)
impossible because of the 2 then K. It has to be k2 for it to be possible.
0grams
Pb(NO3)2 is lead II nitrate. It used to be used to make the color in paint, but it's toxic.
10 NaHso3+4kIo3-----5Na2s2o5+2I2+3H2so4+2k2so4+2H2o