I think that should be 2N2O4+2H2O+O2 --> 4HNO3
But i'm not sure
The chemical equation is:Sn + 4 HNO3 = SnO2 + 4 NO2 + 2 H2O
2 Fe2O3 + 12 HNO3 -> 4 Fe(NO3)3 + 6 H2O
This is a redox reaction where NO2 is oxidized to HNO3 and H2O is reduced to NO. To balance the equation, start by balancing the atoms of each element (N, O, and H) on both sides of the reaction. Then, add electrons to balance the charges. The balanced equation is: 3NO2 + H2O -> 2HNO3 + 2NO + 2H+.
N2O5 + H2O == HNO3 + HNO3 Usually written as N2O5 + H2O = 2HNO3 You have 2 x nitrogen in N2O5 , so 2 x nitrogen in the products, one each in the two molecules of nitric acid. You have 2 x hydrogen in H2O , so 2 x hydrogen in the products, one each in the two molecules of nitric acid. You have 5 oxygens in N2O5 + 1 oxygen in water making for 6 oxygens. These oxygen are equally shared ( 3 each) in the two nitric acid molecules. However, we do not write ' HNO3 + HNO3 ' in chemistry , but use a little bit of 'shorthand' and write it as ' 2HNO3 '. to indicate that there are two(2) molecules of nitric acid formed.
KOH + HNO3 --> KNO3 + H2O -------------------------------------site mis-correcting again. All letters capitalized.
The balanced equation for the reaction between HNO3 and NaHCO3 is: 2 HNO3 + NaHCO3 → NaNO3 + H2O + CO2
Cu + HNO3 = Cu(NO3)2 + NO + H2O
This reaction is:S + 6 HNO3 = H2SO4 + 2 H2O + 6 NO2
The molecular equation for the reaction between nitric acid (HNO3) and potassium hydroxide (KOH) is: HNO3 + KOH -> KNO3 + H2O.
It produces Nitric acid(HNO3) and Nitrous acid(HNO2), when reacted with water
299 H2SO4 + 10 K4Fe(CN)6 + 122 KMnO4 = 60 CO2 + 5 Fe2(SO4)3 + 188 H2O + 60 HNO3 + 162 KHSO4 + 122MnSO4
The acid-base reaction between nitric acid (HNO3) and sodium hydroxide (NaOH) produces sodium nitrate (NaNO3) and water (H2O). The balanced chemical equation for this reaction is: HNO3 + NaOH → NaNO3 + H2O.