H3PO4 + 3NaOH --------> Na3PO4 + 3H2O
H3PO4 + 1 OH- --> H2PO4- + 1 H2O H3PO4 + 2 OH- --> HPO42- + 2 H2O H3PO4 + 3 OH- --> PO43- + 3 H2O
4,1,2
K3PO4 + 3HCl -> 3KCl + H3PO4 Since K on the reactant side has 3 potassium atoms, K on the product side should also have 3 potassium atoms to balance the equation. Since you put the 3 on KCl of the product side, another 3 has to go on the Cl on the reactant side which also matches the 3 hydrogen atoms on the product side in H3PO4. If you check, the equation is now balanced. Everything that appears on the left, equally appears on the right
KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l)
my balance sheet does not balance why?
Na3PO4+H2O->NaOH+H3PO4 just balance it.
H3PO4 + NaOH ----> Na2HPO4 + H2O
NaOH + H3PO4 --> Na3PO4 NaOH + H3PO4 -->
H3PO4 + 3NaOH --------> Na3PO4 + 3H2O
H3PO4 + 1 OH- --> H2PO4- + 1 H2O H3PO4 + 2 OH- --> HPO42- + 2 H2O H3PO4 + 3 OH- --> PO43- + 3 H2O
H3PO4 (aq) + LiOH (aq) ---> H2O(liq) + Li3PO4 (aq) Second opinion: That was pretty close, but Li and H are not balanced. Try this: H3PO4 (aq) + 3 LiOH (aq) ---> 3 H2O (liq) + Li3PO4 (aq)
4,1,2
K3PO4 + 3HCl -> 3KCl + H3PO4 Since K on the reactant side has 3 potassium atoms, K on the product side should also have 3 potassium atoms to balance the equation. Since you put the 3 on KCl of the product side, another 3 has to go on the Cl on the reactant side which also matches the 3 hydrogen atoms on the product side in H3PO4. If you check, the equation is now balanced. Everything that appears on the left, equally appears on the right
One possible reaction is 2 NaOH + H3PO4 = Na2HPO4 + 2 H2O.
KHC8H4O4(aq) + NaOH(aq) → KNaC8H4O4(aq) + H2O(l) NaOH(aq) + KHP(aq) => Na+ + KP- + H2O(l)
Balanced equation:12 HClO4 + P4O10 = 4 H3PO4 + 6 Cl2O7