Mass of Fe=(Mass of Fe2O3)(Mr Fe/ Mr Fe2O3)
2 Al + Fe2O3 ----> Al2O3 + 2 Fe
The reaction is:4 Fe + 3 O2= 2 Fe2O3
The chemical formula is written as:4Fe + 3O2 2Fe2O3. Your welcome
the mineral element found in haemoglobin is iron
2 Fe + 3 CuO -> Fe2O3 + 3 Cu
The reactions are:4 Fe + 3 O2 + 2 H2O = 4 FeO(OH)2 FeO(OH) -------Fe2O3 + H2O
Iron + Oxygen= Iron oxideChemical Equation4Fe + 3O2 --> 2Fe2O3No Problem! :)
nothing yust instead of having Fe you have FeO or Fe2O3
feo2 feo3 feo4
Fe3O4 can be considered to be 1:1 mixture of FeO and Fe2O3. Oxidation number in FeO: +2 for Fe and -2 of O Oxidation number in Fe2O3: +3 for Fe and -2 of O
The charge of iron in FeO is 2+.Iron has also the charge 3+ in other compounds.
There are at least three different iron oxides, with formulas FeO, Fe2O3, and Fe3O4. The equations are: FeO + Ca = CaO + Fe Fe2O3 + 3Ca = 3CaO + 2Fe Fe3O4 + 4Ca = 4 CaO + 3Fe
Rust consists of hydrated iron oxides Fe2O3·nH2O and iron oxide-hydroxide (FeO(OH), Fe(OH)3).
75.89 grams of FeO is equal to 1.06 moles of iron II oxide. In decomposition, there would be 1.06 moles of iron recovered, or 58.99 grams.
Simple - Look at the formulas involved. FeO and Fe2O3 by reducing them in a blast furnace you remove the oxygen so that the become Fe only. The first FeO is black and is Iron Oxide, the other has two atoms of iron combined with three atoms of Oxygen. Fe2O3 is orange due to the formation of rust, and a common form is Haematite.
Fe2O3 + 2Al --> Al2O3 + 2Fe
14.2g Fe2O3 (1mol Fe2O3/159.7g(2mol Fe/1mol Fe2O3) = 0.178 moles Fe