according to my research you calculate it by using these numbers:
16.7 mL x 0.0500 M = 25 mL x m; 0.0334
The molar mass of acetic acid is 60,05 g.
Ch3cooh- mass is 60 as 12+3+12+32+1=60
A home-using acetic acid solution is lesser than 10% w/w.
60.06g
60
Mass isn't lost, it just escapes as a gas
60
The molar mass of acetic acid is 60,05 g.
Ch3cooh- mass is 60 as 12+3+12+32+1=60
A home-using acetic acid solution is lesser than 10% w/w.
60.06g
60
Yes. The baking soda (Na2CO3) and the vinegar (principally acetic acid, CH3COOH) produce carbon dioxide (CO2) and sodium ethoxide (CH3COONa). Mass is always conserved in simple chemical reactions.
To prepare a 0.1 N glacial acetic acid solution, calculate the required mass by multiplying 0.1 moles by the molar mass of glacial acetic acid (60.05 g/mol). Weigh out the calculated mass and add it to a clean container. Dissolve the glacial acetic acid completely by stirring it with distilled water. Transfer the solution to a 1-liter volumetric flask and dilute it to the 1-liter mark with distilled water. Mix thoroughly, label, and store the solution properly, taking necessary safety precautions when handling glacial acetic acid.
The molar mass of ethanoic acid (acetic acid, C2H4O2) is 60.05 g mol−1H2CO3 molar mass 62.03 g mol-1HNO3 molar mass 63.01 g mol−1
The mass of one mole of a substance is its molecular mass in grams. The molecular mass of acetic acid (CH3COOH) is: 12 + (3 x 1) + 12 + 16 + 16 + 1 = 60, therefore, 1 mole of acetic acid has a mass of 60g. (The numbers used in the calculation are the mass numbers of each element)
Molar mass of ethanoic acid = (1x12) + (3x1) + (1x12) + (2x16) + (1x1) = 60 no. of moles = mass/ molar mass = 21.71/60 = 0.362 moles