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Molar mass silver nitrate = 170 g/mole
170 x 2.2 = 374 g
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How many moles are in 680g of AgNO3?
Roughly 4 moles.
How many moles of Ag are produced when starting with 6.2 moles of AgNO3?
6,2 moles of silver
How many moles of silver of ions are presented in 32.46 g of AgNO3?
The number of moles is 0,19.
Determine the number of formula units that are in 0.688 moles of AgNO3?
0.688 moles*6.02x1023=4.14x1023 Formula units
How many silver atoms would be in 4.55 moles of AgNO3?
4.55 moles AgNO3 (1 mole Ag/1 mole NO3)(6.022 X 10^23/1 mole Ag) = 2.74 X 10^24 atoms of silver
How many moles of AgNO3 does 85 grams of AgNO3 represents?
85 grams of AgNO3 represents 0,.5 moles.
How many mL of .117M AgNO3 solution would be required to react exactly with 3.82 moles of NaCl?
Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can
How many moles of agno3 are needed to prepare 0.50 l of a 4.0 m solution?
Molarity = moles of solute/liters of solution or, for our purposes moles of solute = liters of solution * Molarity moles of AgNO3 = 0,50 liters * 4.0 M = 2.0 moles of AgNO3 needed --------------------------------------
How many moles are in 680g of AgNO3?
Roughly 4 moles.
What is the molarity of a solution if 255 grams AgNO3 is dissolved in 1500 mL of solution?
Get moles silver nitrate. 255 grams AgNO3 (1 mole AgNO3/169.91 grams) = 1.5008 moles AgCO3 --------------------------------Now; Molarity = moles of solute/Liters of solution ( 1500 ml = 1.5 Liters ) Molarity = 1.5008 moles AgNO3/1.5 Liters = 1.00 M AgNO3 ---------------------
How many moles of Ag are produced when starting with 6.2 moles of AgNO3?
6,2 moles of silver
How many moles of silver are present in 32.46g of AgNO3?
AgNO3 is 169.87 g/mol. Ag is 107.87 g/mol meaning that Ag is 63.5% of AgNO3. 63.5% of 32.46g is 20.61g. 20.61g / 107.87 g/mol = .191 moles.
How many moles of silver of ions are presented in 32.46 g of AgNO3?
The number of moles is 0,19.
Determine the number of formula units that are in 0.688 moles of AgNO3?
0.688 moles*6.02x1023=4.14x1023 Formula units
How many moles of silver nitrate do 2.8881015 formula untied equal?
2,888.10e15 molecules of AgNO3 equal 0,48.10e-8 moles.
How many moles of AgCl will be produced from 83.0 g of AgNO3 assuming NaCl is available in excess?
X = 0.489 moles of AgCl produced
How much does 13.0 moles of AgNO3 weigh?
13 multiplied by 169.87 (g/mol) = 2208.3g
