I2 will dehydrate the ascorbic acid creating the product dehydroascorbic acid. It can be drawn using arrow formalism
In the presence of sulphuric acid (H2SO4), KI produces HI Since is an oxidizing agent, it oxidizes HI (produced in the reaction to I2). As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4 is used.
The calcium iodide is obtained by the reaction between calcium carbonate (CaCO3) or calcium oxide (CaO) and the hydroiodic acid (HI), not by a direct reaction of the elements.
The chemical reaction is:2 K + I2 = 2 KI
Toward I2(s) production
H2,g + I2,s --> 2HIg
Entropy increases in the reaction.
There will be no reaction between Hydrogen Iodide and sulphuric acid. If the acid are is dilute a soution of both will be formed, if the acid is concentrated these compounds are immiscible. hydrogen iodide and sulphuric acid are actually a product of a reaction (known as the Bunsen reaction) 2H2O + SO2 + I2 → H2SO4 + 2HI
In the presence of sulphuric acid (H2SO4), KI produces HI Since is an oxidizing agent, it oxidizes HI (produced in the reaction to I2). As a result, the reaction between alcohol and HI to produce alkyl iodide cannot occur. Therefore, sulphuric acid is not used during the reaction of alcohols with KI. Instead, a non-oxidizing acid such as H3PO4 is used.
The reaction for MnO2 mixed with KBrO3 and 9M sulfuric acid is as follows: 2KI + MnO2 + H2SO4 --> I2 +MnSO4 + K2SO4 + 2H2O.
B.The reaction will proceed to the left.C.More I2 will form.E.HI will be consumed.
The calcium iodide is obtained by the reaction between calcium carbonate (CaCO3) or calcium oxide (CaO) and the hydroiodic acid (HI), not by a direct reaction of the elements.
Redox reaction.
It is spontaneous.
I is replaced by Cl.So KCl and I2 is formed.
It is spontaneous
The chemical reaction is:2 K + I2 = 2 KI
There is no reaction. But I2 melt in CHCl3.