0
Calcium is 40g per mole (according to the Periodic Table,) so 50/40=1.25 moles.
Wiki User
∙ 8y ago
Wiki User
∙ 8y agoIf Ca is calcium:
Atomic weight of calcium is 40,078.
In mol: 55/40,078 = 1,37
Add your answer:
Earn +20 pts
Mass of 3.400 mol Ca(OH)2?
The mass of 3,400 mol Ca(OH)2 is 251,9 g.
What is the mass in grams of 0.330mol of calcium?
The mass is 0.330 mol Ca (40.08 g/mol) = 13.2 g Ca
What is the mass percent of calcium in calcium suppleiment if 1.15g of CaCO3 is extracted from a 2.70g pill?
1.15 (g CaCO3) / 100.1 (g/mol CaCO3) =1.149*10-2 (mol Ca)1.149*10-2 (mol Ca) = 1.149*10-2 (mol Ca) * 40.08 (g/mol Ca) = 0.4604 g Ca0.4604 g Ca = 0.4604 g Ca / 2.70 g Supplement = 0.1705 * 100% = 17.1% Calcium (m%)
How many moles of Al are in 50g of it?
The atomic mass of Al is 27.0 Amount of Al in a 50g pure sample = 50/27.0 = 1.85mol
How many grams is contained in .27 moles of calcium?
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
Mass of 3.400 mol Ca(OH)2?
The mass of 3,400 mol Ca(OH)2 is 251,9 g.
What is the mass in grams of 0.330mol of calcium?
The mass is 0.330 mol Ca (40.08 g/mol) = 13.2 g Ca
What is the mass percent of calcium in calcium suppleiment if 1.15g of CaCO3 is extracted from a 2.70g pill?
1.15 (g CaCO3) / 100.1 (g/mol CaCO3) =1.149*10-2 (mol Ca)1.149*10-2 (mol Ca) = 1.149*10-2 (mol Ca) * 40.08 (g/mol Ca) = 0.4604 g Ca0.4604 g Ca = 0.4604 g Ca / 2.70 g Supplement = 0.1705 * 100% = 17.1% Calcium (m%)
How many gram of phosphorus are n 58.1 g of calcium phosphate?
58.1g [Ca(PO4)] X 1 mol [Ca(PO4)] X 2 mol (PO4) X 1 mol (P) X 30.97g (P) = 11.6g (P) 310.2g [Ca(PO4)] 1 mol[Ca(PO4)] 1 mol (PO4) 1 mol (P) Sorry about the formatting, im trying to show stoichiometry.
How many moles of Al are in 50g of it?
The atomic mass of Al is 27.0 Amount of Al in a 50g pure sample = 50/27.0 = 1.85mol
What will the volume of 0.50 M solution be if it contains 25 grams of calicum hydroxide?
Ca(OH)2 = 74.093 g/mol 25g / 74.093 g/mol = 0.3374 mol Ca(OH)2 0.3374 mol / 0.5 mol/L = 0.6748 L Ca(OH)2 which is equal to approximately 675 mL, or 680 rounded up.
How many grams is contained in .27 moles of calcium?
(2.7 mol Ca / 1) * (40.078 g Ca / 1 mol Ca) = 108.21 g Ca. After significant figures, the answer is 110 g Ca.
What is the lattice energy of NaBr?
2253kJ/mol Calculation below Ca(2+) + 2 Cl | 242 | Ca(2+) + Cl2 | | | 348.7 * 2 | 1145 2 Cl(-) + Ca(2+) | | Ca(+) + Cl2 | | 590 | Ca(g) + Cl2(g) | 2253 | 178 | Ca(s) + Cl2(g) | | 795 | CaCl2(s)------------
How many moles are in 12.2 grams of calcium?
12.2 g Ca/ 40.08 g/mol = .304 mol
How many grams of Ca-OH-2 are needed to prepare 100 mL of solution of 0.1 M Ca-OH-2?
M = moles/liter 100 ml = 0.1 liter so 0.01 mole NaOH / 0.1 liter = .1 M NaOH you can find how many grams of NaOH in .01 moles by multiplying .01 by the atomic weight of a mole of NaOH, which you can find by adding up the atomic weight of Na, and O, and H.
Determine the number of moles of Cl in 1.9 mol CaCl2?
Ca-1(40.08)g=40.8g/mol of Ca Cl-2(35.45)g=70.9g/mol of Cl2 40.08g+70.9g=110.98g/mol CaCl2 110.98g CaCl2/1mol * 1.9mol =210.86 g of CaCl2
Find the mass of 0.89 mol of CaCl2?
Ca + Cl + Cl = 40.078 +35.453 + 35.453 = 110.984 .89 / 110.984 = 0.008019
