25,5 g Ag/107,8682= 0,236 mol Ag
50g/28g= 1.7857 moles
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
The answer is 3,375 moles oxygen.
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
50g/28g= 1.7857 moles
50 g of NaCl represent 0,856 moles.
0.49038225061051505
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
1 mole Al(CN)3 = 105.03g _ moles = 163g 1 mole Al(CN)3 * 163g / 105.03g 163 moles/105.03 = 1.55 moles
The answer is 3,375 moles oxygen.
9.55 mol of Al
9 grams aluminum (1 mole Al/26.98 grams) = 0.3 moles aluminum ==============
1.5 moles of O2 react with 2 moles of Al 2Al + 1.5 O2 = Al2O3.
50g of what ?
find moles: 20.0 grams of Al @ (27.0 g/mol) = 0.7407 moles of Al by the reaction: 2 moles Al+3CuSO4 → Al2(SO4)3 +3 moles Cu 0.7407 moles of Al produces 3/2 's as many moles of Cu = 1.11 moles of Cu find mass, using molar mass: 1.11 moles of Cu @ (63.5 g/mol) = 70.6 grams of Cu your answer is 70.6 g