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The mass of 3,400 mol Ca(OH)2 is 251,9 g.

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What is the mass of 0.7891 mol of ferric oxide Fe2O3?

Atomic mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g


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What is the mass of 0.7891 mol of ferric oxide?

Atomic Mass of Fe: 55.8g/mol Atomic mass of O: 16g/mol Molecular mass of Fe2O3: 2(55.8)+3(16) = 159.6g/mol mass = Molecular mass x number of moles mass = 159.6g/mol x 0.7891mol = 125.94g


Calculate the mass in grams of 2.60 mol of potassium chloride (KCl)?

To calculate the mass of 2.60 mol of potassium chloride (KCl), first determine its molar mass. The molar mass of KCl is approximately 74.55 g/mol (39.10 g/mol for K and 35.45 g/mol for Cl). Thus, the mass can be calculated using the formula: mass = moles × molar mass. Therefore, the mass of 2.60 mol of KCl is 2.60 mol × 74.55 g/mol = 193.83 grams.


What is the mass in grams of 0.330mol of calcium?

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To calculate the mass of 0.45 mol of ammonium sulfate (NH4)2SO4, you need to know its molar mass. The molar mass of (NH4)2SO4 is 132.14 g/mol. Multiply the number of moles (0.45 mol) by the molar mass to get the mass: 0.45 mol x 132.14 g/mol = 59.46 grams. Therefore, the mass of 0.45 mol of ammonium sulfate is 59.46 grams.


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To find the mass of 0.555 mol of magnesium fluoride (MgF₂), first determine the molar mass. The molar mass of Mg is approximately 24.31 g/mol, and that of F is about 19.00 g/mol, giving MgF₂ a total molar mass of about 24.31 + (2 × 19.00) = 62.31 g/mol. Therefore, the mass of 0.555 mol of MgF₂ is calculated as 0.555 mol × 62.31 g/mol ≈ 34.59 g.


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