First calculate the mass you need from NaCl I will calculate it for you now: 100 cm3= 0,100 L n (NaCl) = 0,1 mol/dm3 * 0,100 L = 0,01 mol m (NaCl) = n*Mm = 0,01 mol * ( 22,99+35,45) g/mol = 0,01 mol * 58,44 g/mol = 0,5844 g You will need 0,5844 g NaCl and you will mix it woth 100 cm3 water
Dissolve 2g of NaCl in 100 cm3 water at normal temperature.
20 g alkali to 250 cm3 solution is more concentrated.
V = 1.78500 × 10-22 cubic centimeters.
I am assuming by "sugar content" you are referring to a solution of sugar and water. Water at around 25 degrees Celsius has a density of 1.0 gram/cm3. The density of solid sugar (sucrose) is around 1.6 grams/cm3. As you dissolve sucrose in water, the density of the resulting solution will naturally increase as you add more and more sugar. As you approach 100% sucrose, the density will approach 1.6 grams/cm3.
The number of grams is the number of cm3. e.g. 300g = 300cm3
Dissolve 2g of NaCl in 100 cm3 water at normal temperature.
This density is 1,0707 g/cm3 at 20 0C.
- freezing point for a solution of 35 g/L NaCl: -2 deg. Celsius- density for a solution of 35 g/L NaCl: 1,025 g/cm3- thermal conductivity for a solution of 35 g/L NaCl: 0,6 W/m.K
- freezing point for a solution of 35 g/L NaCl: -2 deg. Celsius- density for a solution of 35 g/L NaCl: 1,025 g/cm3- thermal conductivity for a solution of 35 g/L NaCl: 0,6 W/m.K
The answer is 0,1648 g NaCl.
Dissolve 0.1g of the powder in ethanol and dilute with distilled water upto 100 cm3
The density of sodium chloride is 2,165 g/cm3.
The sodium chloride density is 2,165 g/cm3 and the melting point is 801 0C.
1 m = 100 cm So 1 m3 = 100*100*100 cm3 = 106 cm3 and 10 m3 = 107 cm3
volume given =27.5mlmolarity of base=0.105find number of moles=moles=vol(cm3)/1000*molarity of NaClmoles=27.5/1000*0.105=3.82 moles of sodium chloride
what is the Ph of a solution containing 5mg/L of hydrochloric acid?
20 g alkali to 250 cm3 solution is more concentrated.