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First calculate the mass you need from NaCl I will calculate it for you now: 100 cm3= 0,100 L n (NaCl) = 0,1 mol/dm3 * 0,100 L = 0,01 mol m (NaCl) = n*Mm = 0,01 mol * ( 22,99+35,45) g/mol = 0,01 mol * 58,44 g/mol = 0,5844 g You will need 0,5844 g NaCl and you will mix it woth 100 cm3 water

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Q: How do you make 100 cm3 of 0.1 mol dm3 NaCl solution?
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