I'm going to assume you want 100ppm by mass, since this is really the only way that makes sense with a solid and liquid.
First, you need to get a fluoride salt. I will use sodium fluoride as an example - it may or may not matter which salt depending on what you're trying to do. Be careful, fluoride compounds can be toxic.
Second, you need to figure out what percentage of the salt is actually fluoride. To do this in our example, first look up the molecular weights of sodium and fluorine on a Periodic Table (the numbers at the bottom of the squares). Sodium (Na) has a molecular weight of 22.989, Fluorine (F) weighs 18.998. Add these to get the total molecular weight of sodium fluoride:
22.989 + 18.998 = 41.987
Now, divide the total weight by the weight of fluorine to get a conversion factor (units of NaF / units of F):
41.987 / 18.998 = 2.21
Third, you need to weigh out your fluorine and water - 100 parts fluorine for every (million - 100) parts water. This reduces to 1 part fluorine per 9,999 parts water (I'll round to 10,000). This is a big difference, so you may need two different scales with different ranges, and it's going to make a bunch of solution.
I'm going to measure in grams, but you could use any measure of weight. First, weight out 10,000 g (10 kg) of water and set it aside. Remember to subtract out the weight of the container when weighing! Next, we need 1 g of fluoride. However, we have sodium fluoride, not fluorine, so we need to use the conversion factor from before:
1 g (F) * 2.21 (NaF / F) = 2.21 g NaF
Weigh out 2.21 g of your salt, add it to the water, and you're done!!!
A problem with this method is you'll end up with a huge amount of solution, and it may be more water than you can easily deal with. To avoid the issue, make the initial solution more concentrated, then dilute it again in a second step. For example, use only 1 / 10th the amount of water, and you'll get a 1,000 ppm solution. You then take 1 / 10th of that solution and add it to 9/10 water in another container. This will give you a 100 ppm solution and you don't have to deal with such a large amount of liquid. You can even add another step for very dilute solutions.
Fluoride ion is a singly negative ion.
The fluoride ion is the ion formed by the element fluorine
The fluoride ion is noted as F- (F minus).
No, The fluoride ion is a reduced form of fluorine.
elements..., but fluoride is a polyatomic ion.
No the fluoride ion is an anion
The fluoride ion is alkaline
Fluoride is the ion of fluorine, which is a nonmetal.
Fluoride Ion
Both fluoride ion and sodium ion are isoelectronic with neon. That means all have 10 electrons.
The sodium ion (Na+) is a cation (positive charge) and the fluoride ion (F-) is an anion (negative charge).
'Fluoride atom'. ???? The fluorine ATOM is 'F' The fluorine molecule is 'F2'. The Fluoride ION is 'F^-' NB When an atom becomes a charged species, it is no longer an atom , but an ION. The suffix '--ide' indicates it is an ion, not an atom. So 'Fluoride atom' is a nonsense. It is either 'Fluoride ion' or Fluorine atom'.