Since HCl is a monoprotic acid, its normality is the same as its molarity. A 4 N solution of HCl is a 4 M solution of HCl as well. If you want to make a liter of a 4 N solution of HCl, you need to dilute a certain volume of a standard solution you already have to one liter (1,000 mL) of the 4 M solution. You could use a standard concentrated solution of HCl that is usually 12 M using the following equation:
(V1)(M1) = (V2)(M2)
V1 = ?
M1 = 12 M
V2 = 1,000 mL
M2 = 4 M
V1 = [(V2)(M2)] / ((M1)
V1 = [(1,000 mL)(4 M)] / (12 M)
V1 = 83 mL
According to the above calculations, to make 1,000 mL (1 L) of a 4 M solution of HCl, you would need to dilute with water 83 mL of 12 M solution of HCl to 1,000 mL (1 L) volume. As stated before, a 4 M solution is also a 4 N solution of HCl.
To make 500mL of 3N NaOH solution, you need to dissolve 15g of NaOH pellets in enough water to make 500mL of solution. Calculate the amount of NaOH needed by using the formula: (g = (N \times M \times V) / 1000), where (N = normality (3N)), (M = molar mass of NaOH (40 g/mol)), and (V = volume in liters (0.5 L)).
1N = 40.0g in 1000mL (1M or 1mol/L)
3N = 120.0g in 1000mL (3M or 3mol/L).
Therefore 3N (3M) in 500mL = 60g NaOH.
Take 28.21 ml Hcl make up to 1000 ml Dis.Water its 3N HCl
25.5ml hcl in 100ml of water
The concentration of this solution (in NaOH) is 40 g/L.
To prepare a 0.4M NaOH solution in 500mL, you would need 20g of solid NaOH. This is calculated by multiplying the molarity by the volume in L and the molar mass of NaOH. (0.4 mol/L) * (0.5 L) * (40 g/mol) = 20g.
To calculate the grams needed, first find the molarity of the solution, which is 125 moles/liter. Then convert the volume to liters (500ml = 0.5 liters) and multiply the molarity by the volume in liters to find the number of moles needed. Finally, multiply the moles by the molar mass of NaOH (40 g/mol) to find the grams needed. In this case, it would be 31.25 grams of NaOH.
To make a 0.1M solution of NaOH, dissolve the appropriate amount of NaOH pellets in water to make a solution of the desired volume. For example, to make 1 liter of 0.1M NaOH solution, dissolve 4g of NaOH pellets in enough water to make 1 liter of solution. Remember to wear appropriate safety gear and handle NaOH with care due to its caustic nature.
To make a 12N NaOH solution, you need to dissolve 480 grams of NaOH solid in enough water to make 1 liter of solution. Make sure to wear appropriate protective gear and handle the concentrated solution with care as NaOH is a strong base that can cause burns.
(100ml)(0.125M NaOH) = (500ml)(X Molarity) Molarity = 0.025 M
The concentration of this solution (in NaOH) is 40 g/L.
To calculate the grams needed, first find the molarity of the solution, which is 125 moles/liter. Then convert the volume to liters (500ml = 0.5 liters) and multiply the molarity by the volume in liters to find the number of moles needed. Finally, multiply the moles by the molar mass of NaOH (40 g/mol) to find the grams needed. In this case, it would be 31.25 grams of NaOH.
(3n)(3n-1) = 3n * 3n - 3n * 1 Now, perform the multiplication: (3n * 3n) = 9n^2 (3n * 1) = 3n So, (3n)(3n-1) simplifies to: 9n^2 - 3n
To prepare a 0.4M NaOH solution in 500mL, you would need 20g of solid NaOH. This is calculated by multiplying the molarity by the volume in L and the molar mass of NaOH. (0.4 mol/L) * (0.5 L) * (40 g/mol) = 20g.
3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (3n + 3 - 3n + 1) = 3n + 2 + (4) = 3n + 6
Is it a. 3n square and 3n ans. 3n b. 3n *2 and 3n ans.3n ans. 3n for both!!
To prepare 2M HCl in 100ml from 36% HCl: Calculate the volume of 36% HCl that you need to obtain the desired concentration by using the formula C1V1 = C2V2. Dilute the calculated volume of 36% HCl with water to reach a final volume of 100ml while maintaining the molarity.
what is 3n times 3n-1
The nth term of this sequence is 3n + 4
No. 3n is not a factor of 3n + 7.
No. 3n is not a factor of 3n + 7.