Take 83.3 mL and add water up to 1000 mL (12 times as much)
The above only helps in one situation... here is the way to do it for any situation
Litersc * Molesc / Litersc = Litersd * Molesd / Litersd
where subscript c is concentrated and subscript d is dillute.
The quicker way to write it is C1V1 = C2V2
so if you are going from 12M and want to go to 1M then it would be:
12M*V1 = 1M*1L
Rearrange and solve:
V1 = 1ML/12M = 0.0833 L = 83.3 mL
combine 100 mL 6 M HCl with 500 mL H2O
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
Get two moles of HCl and add water until the solution is 1 L
1
85 mL of (concentrated, 38%) HCl solution contains 36.5 gram HCl, which dissolved and diluted in up to 1.0 Liter gives you an 1.0 molar solution.
combine 100 mL 6 M HCl with 500 mL H2O
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
Get two moles of HCl and add water until the solution is 1 L
1
pH = -log(0.280) = 0.553
85 mL of (concentrated, 38%) HCl solution contains 36.5 gram HCl, which dissolved and diluted in up to 1.0 Liter gives you an 1.0 molar solution.
0.17 Molar
dilute your HCl solution to 0.2 M HCl solution and then follow above mentioned link : http://delloyd.50megs.com/moreinfo/buffers2.html
When 100cm3 of 1.0 molar of sodium hydoxide solution at 200oc was added to 100cm3of1.0 molar of HCL solution at 200oc,then the temperature of HCL rose to 26.8oc.calculate the standard heat of neutralisation?(Given that the specific heat capacity of water is 4.2KJg-1k-1)
Calculate the weight% of HCl for the amount of solution you want to make up. Calculate how many moles of HCl this is. Determine the molar ratio you want to have, HCl should be in excess and usually 3:1 to 5:1 HCl:ABF will make the solution workable.
Molar mass of HCl = 1 + 35.5 = 36.5 Number of moles of HCl = mass / molar mass = 85.6 / 36.5 = 2.345 moles Molarity = number of moles / Volume = 2.345 / 0.385 = 6.091 M
14.5% HCL by weight, which is roughly a 4.2 molar solution