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What is the molar concentration of a solution made by dissolving 4.0g of NaOH in enough water to make 1.0 L of solution?
C1V1 = C2V24 x .04 = 1 x V2V2 = (4 x .04)/1= 160mLTherefore the volume of water that needs to be added is 120mL (minus the original volume).
What is the molarity of a solution prepared by dissolving 20.00g CaCl2 in enough water to make 1.00L of solution?
20.2 g of CuCl2 = .1502 mol CuCl2 M=mol/L M=.1502 mol/L
Find volume of sulphuric acid of concentration 32 percent weight and density 1.531 gram per liter diluted to 5.8 liter to be 1.5 molar?
Initially, the mass of H2SO4 required to prepare 5.8 liters of 1.5 molar solution should be calculated. Number of moles present in 5.8 L of 1.5 molar solution = 1.5 mol L-1 x 5.8 L= 8.7 molMolar mass of H2SO4 = 98 g mol-1Therefore, mass of H2SO4 in the above solution = 8.7 mol x 98 g mol-1= 852.6 gMass of H2SO4 in the original solution per litre = 1.531 g x 32/100= 0.48992 gVolume of sulphuric acid required to prepare 1.5 molar solution = 852.6 g/0.48992 g = 1740.3 L
What is the molarity of a solution that has 6 mol of CaCl2 in 3 kg of water?
The molarity is 2 mol/L.
The active mass of 22.2 lit of carbondioxied gas at 273k is?
0.045 mol L 0.5. Mol.
What volume of 18.0 mol/L sulfuric acid is required to prepare 28.2 L of 0.126 mol/L H2SO4?
202.44
Calculate the volume of a 0.05000 mol/l stock solution of CuSO4 (aq) required to prepare 100.0 ml of a 0.005000 mol/l solution?
For starters, you know that 0.05000-mol L − 1 solution of copper(II) sulfate contains 0.05000 moles of copper(II) sulfate, the solute, for every 1 L = 10 3 mL of the solution.
How many moles of NaOH are needed to prepare 2.00 L of a .250 M NaOH solution?
Molarity equals mole per liter M = mol/L So solve for moles by multiplying liters to the other side of the equation and you get: mol=ML Plug in your numbers mol=0.250M*2.00L mol=0.5 or 19,99855 grams = aprox. 20 grams
What volume of a 4.0 m stock solution of hno3 is needed to prepare 4.5 l of a 2.5 m hno3 solution?
Applying the equation for a dilution (c1.V1 = c2.V2) gives4.0(mol/L)*V1(L) = 2.5(mol/L)*4.5(L) so V1 = 2.5*4.5/4.0 = 2.813 L = 2.8 litres
How many grams of ammonia are presented in 5.0 l of a 0.050 m solution?
4.25 grams. .050 M = .050 mol/1 L 5.0 L x .050 mol/L (cancel out L to get mol as a unit)= .25 mol Atomic mass of Ammonia (NH3)= 17 g/mol .25 mol x 17 g/mol (cancel out mol to get g as a unit)= 4.25 g
When was Wouter Mol born?
Wouter Mol was born on 1982-04-17.
How many grams of KBr are required to make 750.0 mL of solution that is 0.0552M molar mass of KBr 119.00gmol?
Multiply the molarity (M, which is in mol/L) with the volume (in L) to get the number of moles needed. Then multiply the result with the molar mass. If you look at the units they will cancel to give an answer in grams. (mol/L)*(L)=mol, (mol)*(g/mol)=g So for the numerical answer you get (0.0552 mol/L)*(0.750 L)*(119.00 g/mol)= 4.93 g KBr
What is the molar concentration of a solution made by dissolving 4.0g of NaOH in enough water to make 1.0 L of solution?
C1V1 = C2V24 x .04 = 1 x V2V2 = (4 x .04)/1= 160mLTherefore the volume of water that needs to be added is 120mL (minus the original volume).
How many mL of water should be added to 50.0 mL of a 15.0 M H2SO4 solution to give a final concentration 300m?
2.5 0.05 L (50 mL) * 15 Mol/L= 300 Mol/L * X litres (0.05 L * 15 Mol/L) / 300 Mol/L = 0.0025 L or 2.5 mL
How many moles of HCl are dissolved in 2.0 L of 0.25 M HCl solution?
0.5 Moles If you have a 0.25 M solution, you have 0.25 mol/dm3, or 0.25 moles in 1 L (0.25 mol/L) If you have 2 L of solution, you have 2 L x 0.25 mol/L = 0.5 mol The L's cancel out, and you're left with moles.
How to prepare ammonium hydroxide solution?
You will mix NH4OH with water. To get a specific concentration you will need to calculate the number of moles required and covert this to a mass. Use the molar mass of NH4OH. eg. 100 mL of 0.5 mol/L NH4OH -> 35.06 g/mol x 0.5 mol/L x0.100 L Notice the units cancel to g. Obtain this amount using a balance and add water to 100mL.
What is the molarity of 6 moles (mol) of NaCl dissolved in 2 L of water?
This molarity is 3 mol/L.
