To prepare 100ml of 0.5N HCl solution, you would need to dilute concentrated HCl (37%) with distilled water in a volumetric flask. Measure 4.2ml of concentrated HCl, add it to the volumetric flask, and then dilute with distilled water to bring the total volume to 100ml. Mix well to ensure uniform concentration.
To prepare 100 ml of 1N HCl, you would need to dilute 8.4 ml of concentrated hydrochloric acid (37% w/w) with distilled water to a total volume of 100 ml.
Oh, dude, it's simple! To make 2M HCl in 100ml from 36% HCl, you'd need to dilute the 36% HCl with water. Just mix 5.56ml of 36% HCl with 94.44ml of water, and voila, you've got yourself some 2M HCl. It's like making a fancy cocktail, but with chemicals!
to prepare 100ml of 100mM Trissolution: Mol wt of Tris=121.14121.14g in 1000ml ----> 1M12.11g in 100ml -------->1M1M=1000mM121.1g---->1000mM12.11g ----------->100mM1.211g in 100ml and 100mM Tris
To prepare 100ml of 0.5N HCl solution from a stock solution of 5.0N HCl, you need to dilute the stock solution with water. To calculate the volume of stock solution needed, you can use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the desired concentration, and V2 is the final volume of the diluted solution. So, V1 = (C2 * V2) / C1 = (0.5 * 100) / 5 = 10ml of the stock solution. Dilute this 10ml of stock solution to 100ml with water.
No. The heat of reaction for 50mL of each will be multiplied by 2 for 100mL of each since heat of reaction is really on a per mole product basis, and there will be twice as many moles of both HCl and NaOH in 100mL as in 50mL.
To prepare 100 ml of 1N HCl, you would need to dilute 8.4 ml of concentrated hydrochloric acid (37% w/w) with distilled water to a total volume of 100 ml.
Oh, dude, it's simple! To make 2M HCl in 100ml from 36% HCl, you'd need to dilute the 36% HCl with water. Just mix 5.56ml of 36% HCl with 94.44ml of water, and voila, you've got yourself some 2M HCl. It's like making a fancy cocktail, but with chemicals!
to prepare 100ml of 100mM Trissolution: Mol wt of Tris=121.14121.14g in 1000ml ----> 1M12.11g in 100ml -------->1M1M=1000mM121.1g---->1000mM12.11g ----------->100mM1.211g in 100ml and 100mM Tris
Ah, preparing a 0.02 M solution of HCl is a wonderful journey. Simply measure out the correct amount of hydrochloric acid and dilute it with water until you reach the desired concentration. Remember to handle chemicals with care and always wear appropriate safety gear. Happy experimenting, my friend!
To prepare 100ml of 0.5N HCl solution from a stock solution of 5.0N HCl, you need to dilute the stock solution with water. To calculate the volume of stock solution needed, you can use the formula C1V1 = C2V2, where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the desired concentration, and V2 is the final volume of the diluted solution. So, V1 = (C2 * V2) / C1 = (0.5 * 100) / 5 = 10ml of the stock solution. Dilute this 10ml of stock solution to 100ml with water.
No. The heat of reaction for 50mL of each will be multiplied by 2 for 100mL of each since heat of reaction is really on a per mole product basis, and there will be twice as many moles of both HCl and NaOH in 100mL as in 50mL.
To prepare a 3% solution of sulfosalicylic acid in 100ml, you would need to dissolve 3g of sulfosalicylic acid in enough water to make a total volume of 100ml. Stir thoroughly until the powder is completely dissolved to ensure a uniform solution.
5g TCA per 100ml of water
100 M HCl don't exist.
To prepare 6N HCl from 1N HCl, you can dilute the 1N HCl by adding 6 times the volume of water to the 1N HCl solution. For example, mix 1 volume of 1N HCl with 6 volumes of water to get a final concentration of 6N HCl. Make sure to add acid to water slowly with stirring to avoid splashes and heat generation.
520 ml of HCl in 480 ml of water=1000ml = 5 N
1.21 g Tris-HCl, QS water to 1L. Scale appropriately.