Want this question answered?
Hi, 6N NaOH = 6M NaOH 6M NaOH are 6 moles in 1L Mw (NaOH) = 39.88 gr/mole so: m = n x MW = 6 x 39.88 = 239.28 gr NaOH. :)
MaVa=MbVb (6.0M NaOH)(x)=(0.10M solution)(1.0L) x=0.017L of 6.0M NaOH Convert to mL (1000mL in 1L) 17mL of 6.0M NaOH
80g of NaOH dissolved in 250ml. of water find the molarity of this solution ?
One Mole of Sodium Hydroxide NaOH= 40.00g/l =1N (8.0g NaOH in 100.0ml of water)= 2N NaOH or (80g of NaOH in 1L of water)= 2N NaOH
a solution of 0.1M NaOH has been prepared.How would you make 1L of the same solution
Hi, 6N NaOH = 6M NaOH 6M NaOH are 6 moles in 1L Mw (NaOH) = 39.88 gr/mole so: m = n x MW = 6 x 39.88 = 239.28 gr NaOH. :)
MaVa=MbVb (6.0M NaOH)(x)=(0.10M solution)(1.0L) x=0.017L of 6.0M NaOH Convert to mL (1000mL in 1L) 17mL of 6.0M NaOH
80g of NaOH dissolved in 250ml. of water find the molarity of this solution ?
One Mole of Sodium Hydroxide NaOH= 40.00g/l =1N (8.0g NaOH in 100.0ml of water)= 2N NaOH or (80g of NaOH in 1L of water)= 2N NaOH
a solution of 0.1M NaOH has been prepared.How would you make 1L of the same solution
Mol. Wt 60.0 So 60.0 gm in 1L is 1M 60*6= 360gm in 1L is 6M urea
First take 170g of NH3 . Then dissolve in 1L of water
Given: 27 mL of NaOH, 0.45M; 20 mL HCI Need: M of HCI 27 ml NaOH*(1 L NaOH/1000mL NaOH)*(0.45M NaOH/1L NaOH)*(1mole HCI/1 mole NaOH)=0.012 0.012/0.02=0.607 M HCI (or rounded 0.61 M HCI)
Dissolve 40 grams of solid NaOH into enough water that it dissolves completely. Transfer this to a volumetric flask. Then add water until the volume of the solution is 1 liter. Care is needed as heat is generated which affects the volume. It is best to make up with water to about 2 cm short of the mark, allow to cool and then add the balance of the water.
Dissolve 294,185 g of potassium dichromate in 1L demineralized water.
Dissolve 0,788 g DPPH in 1L ethanol.
1.21 g Tris-HCl, QS water to 1L. Scale appropriately.