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Dissolve 294,185 g of potassium dichromate in 1L demineralized water.
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How do you prepare 1 molar iodoacetamide solution?
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
How do you calculate molarity for milli molar and nano molar solution?
The term molar it refers a form to know the concentration of a solution, and it is equivalent to a molar unit in a litre of solvent 1 Molar (1M) = 1 mole (molecular weight from the structure you are interested in) / 1000 mL or 1 L. Milimolar is the thousandth part from a solution 1M
How is a 5 molar solution different than a 1 molar solution of koolaid?
They're actually exactly the same in that neither of them exists.
What is the molar solution?
When we say that a solution has a given molarity, it tells you how much of a given substance is dissolved into the solution. A 1.0 molar solution has one mole of a substance dissolved into one liter of water.
Find volume of sulphuric acid of concentration 32 percent weight and density 1.531 gram per liter diluted to 5.8 liter to be 1.5 molar?
Initially, the mass of H2SO4 required to prepare 5.8 liters of 1.5 molar solution should be calculated. Number of moles present in 5.8 L of 1.5 molar solution = 1.5 mol L-1 x 5.8 L= 8.7 molMolar mass of H2SO4 = 98 g mol-1Therefore, mass of H2SO4 in the above solution = 8.7 mol x 98 g mol-1= 852.6 gMass of H2SO4 in the original solution per litre = 1.531 g x 32/100= 0.48992 gVolume of sulphuric acid required to prepare 1.5 molar solution = 852.6 g/0.48992 g = 1740.3 L
Why you can use 4.9035 g K2Cr2O7 to prepare 0.1 n solution?
The equivalent of potassium dichromate is the molar mass/6: 294,1846/6=49,307666. For a 0,1 N solution: 49,30766/10 = 4,93076 g
How prepare 0.1 n k2cr2o7?
Weigh 4.9035g K2Cr2O7 make up to 1 liter
Can you prepare 1 liter of a .5-molar glucose solution?
The formula is C6H12O6 which is 180g/mole. Divide that in half for 90g in one liter of water for a 0.5 molar solution
How do you prepare a 2 molar salicylic acid solution?
take 276 gm of salicylic acid in 1000 ml water to prepare 2M solution of the salicylic acid.
How do you make 0.25N K2Cr2O7 solution?
1N of k2cr2o7=49.09 gm/1 L 0.25N=12.2725 gm of k2cr2o7 in 1 L of water.
How do you prepare 0.2 milli molar DPPH solution in ethanol?
Dissolve 0,788 g DPPH in 1L ethanol.
How would you prepare a 1 mole solution of lactose?
Find out the molecular weight of LactoseAdd that many grams of Lactose into a 1000ml volumetric flaskMake up the volume to 1000ml with waterYour 1 Molar solution of Lactose is ready---------------The molar mass of lactose is 342,3 g/mol; the solubility of lactose is 216 g/L at20 0C. Consequently you cannot prepare a molar solution of lactose.
How much water should be added to 98 mg of sodium azide to give a 1 molar solution?
See Related Questions link "How do you prepare a solution of a specific concentration?"
How many grams of potassium are in 12.5 g potassium dichromate?
potassium dichromate- K2Cr2O7 12.5 grams K2Cr2O7 *(1 mol K2Cr2O7/294 grams K2Cr2O7)= .0425 mols K2Cr2O7 There's two mols of K (potassium) for every 1 mol of K2Cr2O7 (Potassium Dichromate) so you multiply the K2Cr2O7 by two to get mols of K .0425 mols K2Cr2O7*(2 mols K/1 mol K2Cr2O7)=.085 mols K Multiply by the molar mass of K to get grams .85 mols K*(39 grams/1 mol K)= 3.32 grams potassium
How do you prepare 1 molar iodoacetamide solution?
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
What is the molar mass of a solution containing 2000 grams?
Only a compound has a molar mass not a solution.
What is principle of potassium dichromate in COD estimation?
The titer volume of the sample gives the volume of Ferrous Ammonium Sulphate required to react with the excess potassium dichromate in the solution. Similarly, the titer volume for the blank (distilled water) gives the volume of Ferrous Ammonium Sulphate required to react with the excess potassium dichromate in the blank. The equation for the titration can be expressed as: Cr2O72 -- + FeSO4 (NH4)2SO4 = Cr+ + NH4+ + Fe 3+ From above equation it can be seen that one molecule of dichromate corresponds to one molecule of Mohr's salt. Thus, the difference in volume of excess K2Cr2O7 reacting with Mohr's solution can be calculated from the expression: = (Original vol. K2Cr2O7 -- vol. of K2Cr2O7 used for oxidation) solution - (Original vol. K2Cr2O7 -- vol. of K2Cr2O7 used for oxidation) blank = (Vol. of K2Cr2O7 used for oxidation) blank - Vol. of K2Cr2O7 used for oxidation) solution Hence, the difference in the titer volume for the solution and the blank is used to find out the Chemical Oxygen Demand directly.
