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How much glucose powder in .5 of water for a 1 molar solution?
To prepare a 1 molar solution, you would need to dissolve 180 grams of glucose powder in enough water to make a final volume of 0.5 liters.
How do you prepare 1 molar iodoacetamide solution?
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
How is a 5 molar solution different than a 1 molar solution of koolaid?
They're actually exactly the same in that neither of them exists.
What is the molar solution?
When we say that a solution has a given molarity, it tells you how much of a given substance is dissolved into the solution. A 1.0 molar solution has one mole of a substance dissolved into one liter of water.
Find volume of sulphuric acid of concentration 32 percent weight and density 1.531 gram per liter diluted to 5.8 liter to be 1.5 molar?
Initially, the mass of H2SO4 required to prepare 5.8 liters of 1.5 molar solution should be calculated. Number of moles present in 5.8 L of 1.5 molar solution = 1.5 mol L-1 x 5.8 L= 8.7 molMolar mass of H2SO4 = 98 g mol-1Therefore, mass of H2SO4 in the above solution = 8.7 mol x 98 g mol-1= 852.6 gMass of H2SO4 in the original solution per litre = 1.531 g x 32/100= 0.48992 gVolume of sulphuric acid required to prepare 1.5 molar solution = 852.6 g/0.48992 g = 1740.3 L
Why you can use 4.9035 g K2Cr2O7 to prepare 0.1 n solution?
To prepare a 0.1 N solution of K2Cr2O7, you need to calculate the molar mass of K2Cr2O7 and use the formula for normality. By dividing the given weight by the molar mass, you can determine the number of moles present, and then calculate the normality using the volume of the solution.
How do you make 0.25N K2Cr2O7 solution?
To prepare a 0.25N K2Cr2O7 solution, you would dissolve 12.43 grams of K2Cr2O7 in enough water to make 1 liter of solution. This will give you a molarity of 0.25N for potassium dichromate (K2Cr2O7) in the solution.
How prepare 0.1 n k2cr2o7?
To prepare a 0.1 N solution of K2Cr2O7 (potassium dichromate), you would need to dissolve 4.903 grams of K2Cr2O7 in enough water to make 1 liter of solution. Weigh out the exact amount of K2Cr2O7 using a balance, then dissolve it in water and make up the volume to 1 liter. This will give you a 0.1 N solution of K2Cr2O7.
How many grams of potassium are present in 21.6 g of K2Cr2O7?
To find the amount of potassium in K2Cr2O7, calculate the molar mass of K2Cr2O7 first. The molar mass of K2Cr2O7 is 294.2 g/mol. Potassium accounts for 239.1 g/mol = 78.2 g/mol in K2Cr2O7, so in 21.6 g of K2Cr2O7, there are 21.6 g * (239.1 g/mol / 294.2 g/mol) = 5.77 g of potassium.
How many grams of potassium are in 24.1 g of K2Cr2O7?
The molecular weight of K2Cr2O7 is: 2(39.0983 g K/mole) + 2(51.9961 g Cr/mole) +7(15.9994 g O/mole) = 294.1846 g/mole thus 24.1 g of K2Cr2O7 is 0.08192 moles. Since it is 2(39.0983 g K/mole) that would mean you have 6.406 g of K (potassium)
How do you prepare a molar solution?
To prepare a molar solution, you need to measure the correct amount of solute (substance being dissolved) in grams and dissolve it in a specific volume of solvent (usually water) to reach the desired molarity. Molarity is the number of moles of solute per liter of solution. You can use the formula: Molarity (M) moles of solute / liters of solution.
Does molarity and normality is same in K2Cr2O7?
No, molarity and normality are not the same in K2Cr2O7. Molarity is the concentration of a solution expressed in moles of solute per liter of solution, while normality is a measure of concentration based on the equivalents of a solute in a solution. In the case of K2Cr2O7, as it has more than one ion that can undergo reaction, the normality would be different from the molarity.
How many grams of CoCl2 6H2O are needed to prepare 50.0ml of a 0.30M CoCl2 solution?
To determine the mass of CoCl2 6H2O to prepare a 0.30M solution in 50.0ml, we first calculate the molar mass of CoCl2 6H2O. The molar mass is 237.93 g/mol, so for a 0.30M solution in 50.0ml, we can use the formula: mass = molarity x volume (L) x molar mass. Therefore, the mass of CoCl2 6H2O needed is 3.57 grams.
How much glucose powder in .5 of water for a 1 molar solution?
To prepare a 1 molar solution, you would need to dissolve 180 grams of glucose powder in enough water to make a final volume of 0.5 liters.
How do you prepare 0.2M of anhydrous of sodium thiosulphate?
To prepare 0.2M solution of anhydrous sodium thiosulfate (Na2S2O3), you dissolve 24.6g of anhydrous Na2S2O3 in distilled water and dilute it to 1 liter. This is the molar mass method, where molar mass of Na2S2O3 is 158.10 g/mol.
How many grams of oxygen will be in 2 moles of potasium dichromate?
In potassium dichromate (K2Cr2O7), the molar mass is 294.18 g/mol. Therefore, 2 moles of K2Cr2O7 will contain 2 x 294.18 = 588.36 grams of the compound. Since there are 7 oxygen atoms in each molecule of K2Cr2O7, the total mass of oxygen in 2 moles will be 7 x 16 (molar mass of oxygen) x 2 = 224 grams.
How many grams of KCl is needed to make 2 molar solution in 1 liter of water?
To prepare a 2 M solution of KCl in 1 liter of water, you would need to dissolve 149.5 grams of KCl. This is because the molar mass of KCl is approximately 74.5 g/mol, and 2 moles of KCl are needed to prepare a 2 M solution in 1 liter of water.
