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If you are asking what percent of H2SO4 that you have, I would need to know that volume of the 5M H2SO4
con.H2SO4 is 98%(v/v)ie 980ml/litre.or 980X1.84(specific gravity of H2So4)ie wt/litre is 1803.2Normality= wt per litre/ Eq.wtie 1803.2/49=36.8 NHence con H2So4 is 36.8 NTo prepare 5 N , It has be diluted 7.36 times with water68
7n h2so4
0.08 n
H2SO4 releases two hydrogen ions into solution. Therefore its Normality is twice its Molarity. Or to answer the question, the molarity is half the normality.
If you are asking what percent of H2SO4 that you have, I would need to know that volume of the 5M H2SO4
con.H2SO4 is 98%(v/v)ie 980ml/litre.or 980X1.84(specific gravity of H2So4)ie wt/litre is 1803.2Normality= wt per litre/ Eq.wtie 1803.2/49=36.8 NHence con H2So4 is 36.8 NTo prepare 5 N , It has be diluted 7.36 times with water68
If you want all the H2SO4 to react, you first need a balenced chemical equasion. Mg + H2SO4 --> MgSO4 +H2 Then you calculate using mole ratios moles is expressed as n. n Mg/1 =n H2SO4/1 n Mg= 0.2mol It's the same because there are no coefficients in front of the reactants.
Mix 1 part 5,25 N H2SO4 with 4,25 parts water to obtain 1 N H2SO4.
7n h2so4
0.08 n
N stands for molality and it indicates the number of moles of a substance in a unit mass of the solution.
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N. Ravi was born on 1948-01-01.
0.1 N means you have a hydronium ion concentration of 0.1 mole/L. Since sulfuric acid is a diprotic acid, you get 2 moles of ionizable protons per mole a sulfuric acid. Meaning, you only need a concentration of 0.05 M sulfuric acid to obtain 0.1 N sulfuric acid. [10 L] * [0.1 mole H+/L] * [1 mole H2SO4/2 mole H+] * [98.08 g/mole H2SO4] * [1 mL/1.84 g H2SO4] = 26.65 mL H2SO4 required to make 10 L 0.1 N H2SO4.
H2SO4 releases two hydrogen ions into solution. Therefore its Normality is twice its Molarity. Or to answer the question, the molarity is half the normality.
A)1. H2SO4 is the solute2. Water is the solvent3. Molarity = moles of solute / liter of solution = n / V(Note the case of the letters is important in science. N stands for Normal in chemistry a type of concentration, n stands for number of moles)Rearrange the formula to find nn = M x VHere are the known values,M = 3.5Mn = x molV = 1.00LPlug it in and solve for n (the number of moles of H2SO4 in the solution)n = 3.5M x 1.00 L = 3.50 mol of H2SO4Molecular mass of H2SO4 is 1g/mole H x 2 + 32.1g/mol S + 16g/mol O x 4 = 98.1g/mol H2SO4mass = number of mole x relative molecular massmass = n x 98.1g/molmass = 98.1g/mol H2SO4 x 3.50mol H2SO4= 343g H2SO4