Release the projectile at a 45 degree angle.
lamda /2
100meter
Rule of thumb is no more than 50 feet.
Poisson ratio of most linear elastic material can be anywhere between 0 and 0.5.
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Hello: * Yes, the angle of a catapult does affect the distance. And this applies to both changing the angle of the catapult and changing the angle of the terrain under the catapult. If you shoot the catapult at say 45 degrees, you have very good distance. If you shoot it at 30 degrees, while it may be further, it would be lower to the ground and perhaps not travel as far hitting trees and running into wind-shear. If you shoot at say 80 degrees, while the lob goes high up in the air, it won't travel very far. So your best bet, for maximum distance, is to take your catapult to the highest possible altitude, aim for 45 degrees, taking into account the wind direction and speed, and lob away. Don't hit anyone. :) Answer Actually, the maximum distance that can be achieved from a catapult is at an angle of 45 degrees. Every degree increase from 0 up to 45 approaches the maximum distance that something can be thrown. Every degree from 45 to 90 decreases the distance.
By laws of physics, the angle at which something is launched into the air affects how far it will travel. Not taking into account air resistance, 45 degrees would be the ideal angle for maximum distance.
You cant it comes automatically the maximum is 5
Well, yes. This is because each rubber band has a maximum amount of force it can transfer before it snaps. So more rubber bands, more force and more distance.
Yes, but it wouldn't be a total solar eclipse. It would be an annular eclipse. The Sun is so far away that the difference between its size when it's at its maximum distance versus its minimum distance is small. The Moon, on the other hand, is about 30% smaller when at its maximum distance than it appears at its minimum distance. At its maximum distance, it appears smaller than the sun, and thus can't fully cover the Sun's disc.
I think the maximum distance is 1000,000,000,000 feet
Maximum possible vacuum is -0.1 Mpa
Usually yes...but it depends on the angle of trajectory, weight and aerodynamics of the thing being catapulted, the length of the "arm" of the catapult, and the amount of force that the catapult is set to hurl the object. Example: a feather on the 10lb catapult which is set at a high trajectory and a low force will go almost nowhere while a stone from a 3 pound catapult will go much farther if it is set on a perfect trajectory and maximum force.
The maximum distance is called its peak. The distance between the wave's positive and negative peaks is its amplitude.
Approximately the distance between this answer and your question.
The suggested maximum distance for this phone is eighty feet, though reception fades as distance increases.
this region is called the linear elastic region as such it is the linear elastic stress.