Basically if you know the Voltage supply and the power used by an appliance then you use the formula for power which is Power = Volts x Amps.
Rearrange so Amps (current) = Power / Volts
If power was 2400 Watts and Volts was 240 the Current would be 2400 / 240 = 10 Amps
with an ammeter
wattage is voltage and amperage multiplied. example V/A=W or 120v x 20a=2400 watts
If you add one extra bulb and the voltage remains constant, then you have doubled the current drained from the regulator. 12 Volt and One 12 Watt lightbulb drains 1 Ampere Current. 12 Volt and Two 12 Watt light bulbs drains 2 Ampere Current. However: If having a 24 volt powersource and you add two 12 Volt 12 Watt in serial, then you still only drain 1 Ampere Current. NOTE: Wattage and Voltage of bulbs may be different even if the sockets are the same. Lower voltage on the bulb will increase the current drain, if voltage is a lot lower it might cause the circuit delivering voltage to burn out or blow a fuse. It can also quickly burn the bulb, sometimes in a fraction of a second. It will however do little damage to add a bulb with higher voltage than the circuit is designed for. You will then only observe that you do not get the light you might hope for. Total Current/Ampere= Combined Wattage divided by Voltage Total Wattage = Combined Current or Ampere multiplied by Voltage. Regards.
If you add one extra bulb and the voltage remains constant, then you have doubled the current drained from the regulator. 12 Volt and One 12 Watt light bulb drains 1 Ampere Current. 12 Volt and Two 12 Watt light bulbs drains 2 Ampere Current. However: If having a 24 volt power source and you add two 12 Volt 12 Watt in serial, then you still only drain 1 Ampere Current. NOTE: Wattage and Voltage of bulbs may be different even if the sockets are the same. Lower voltage on the bulb will increase the current drain, if voltage is a lot lower it might cause the circuit delivering voltage to burn out or blow a fuse. It can also quickly burn the bulb, sometimes in a fraction of a second. It will however do little damage to add a bulb with higher voltage than the circuit is designed for. You will then only observe that you do not get the light you might hope for. Total Current/Ampere= Combined Wattage divided by Voltage Total Wattage = Combined Current or Ampere multiplied by Voltage. In simpler words: If you double the bulbs, twice the current is drained from the battery
All you can do is get in the ballpark knowing resistance of windings and the supply voltage. Current = Voltage divided by resistance. Wattage = voltage x current x power factor. For a motor the power factor is between zero and sone number less than one, with one being just a resistive load. So if you calculate the current and use a PF = 1 you can get worse case wattage.
The current will drop. Y??See it this way - resistance is something that opposes current flow. Voltage is the one that helps the current to get across the resistance. So if u have a high resistance, u need a high voltage to get the same current across.But all the values are solely dependent on the output required.Hope that helps.
Current depends on the Wattage and the voltage rating of the device.
Current.
You'd need to know either the resistance or the wattage of the circuit. Ohm's Law: Current = Voltage divided by resistance or Current = Power divided by Voltage
No, the electrical meter reads watts by multiplying the voltage and the amperage used in electrical circuits. Using oversize wire does not govern the amperage flow to the load. The load resistance in the circuit is what governs the amount of current that flows through the wire. This current in the load circuit is multiplied by the voltage applied to the circuit at the electrical meter. The product of this multiplication is wattage, multiplied by the amount of time the load is on, is what the electrical utility bill is based on.
A watt is a measure of electrical power. If you want to know how much current a circuit will draw, and you have wattage ratings of appliances or devices then you can calculate the current. {Power = Voltage × Current}. On a 110 Volt circuit, you can add up the wattages and then divide by 110 volts, to get current in amperes.
Common sense with electrical systems dictates that current in a circuit be limited to 80% of nameplate (20A). The number of 150W lamps will be limited to 12 in this scenario. This answer can be superseded by local ordinance.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
Current or amperage, is wattage divided by voltage. 60 / 120 = .5 amp.
If running at 110V, that is 10Amps. Wattage = Voltage x Current Current = Wattage / Voltage - Neeraj Sharma
In its simplest form the equation to calculate the wattage of an electrical appliance is: Watts = voltage x current. If the appliance is in a AC supply use the Route mean square voltage (the stated AC voltage).
since circuit breaker consists of coils they get heated up when high current flows, when this happens the coil get energised and pull the moving contacts to open thus the circuit breaker opens when high current flows.