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What is addressing mode 8086?
Immediate addressing mode is when one of the operands is "immediately" located after the opcode. It is more correct to say that the operand is part of the instruction.
What is addressing mode in 8086?
Immediate addressing mode is when one of the operands is "immediately" located after the opcode. It is more correct to say that the operand is part of the instruction.
Can both operand 1 and operand 2 be memory in 8086?
Yes, both operand 1 and operand 2 can be in memory in the 8086. An example is the string copy primative, which takes source and destination operands to be memory pointed to by DS and ES.
Difference between code segment and data segment of an instruction?
In the 8086/8088 microprocessor, the code segment is used to fetch the opcode and any additional instruction bytes that might be part of the instruction, while the data segment is used to fetch and/or store any operand bytes that the instruction requires to be manipulated.This is in the case of no segment override prefix.
Describe the functions of the 8086 queue?
The 8086/8088 instruction queue is a buffer that holds opcode bytes that have been prefetched by the bus interface unit. This speeds up operations of the processor by helping to reduce fetch latency, i.e. to improve the probability that an opcode byte fetched by the processor is already available.
What is meaning of byte ptr in 8086?
byte ptr is an assembler directive that says the following operand is an address of a byte.
What is 3 byte instruction in microprocessor?
A two-byte instruction gives the specific function instruction in two bytes, or two words. The first specifies the opcode, which tells the microprocessor what operation will occur. The second specifies the operand, or the data that the operation is done on.
What are the roles of BHE in 8086 microprocessor?
BHE is used to enable the high order bus so as to differentiate between a word operation and a byte operation.
What is the meaning of 0FH in 8086 microprocessor?
0FH is a literal constant for the integer value 15. In the 8086/8088, as an opcode, it is the lock prefix, which means that no other CPU or bus master can take the bus during the execution of the instruction.
What is an instruction queue in 8086?
The 8086/8088 instruction queue is a buffer that holds opcode bytes that have been prefetched by the bus interface unit. This speed up operations of the processor by helping to reduce fetches latency, i.e. to improve the probability that an opcode byte fetched by the processor is already available. This works best when there is no branching, as a branch would invalidate the queue. Advanced processors attempt to "predict" the branch, making the probability even better.
Show the difference between Motorola 6800 and Intel 8086?
Comparision between motorola6800 And Intel 8086
What is the basic difference between MUL and IMUL instruction in 8086 microprocessor?
mul is used for unsigned multiplication whereas imul is used for signed multiplication. Algorithm for both are same, which is as follows:when operand is a byte:AX = AL * operand.when operand is a word:(DX AX) = AX * operand.But, the difference is that mul instruction multiplies only unsigned numbers whereas imul instruction does the same for signed numbers.
