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How does a diverging lens can form a real image of a real object?
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An object 51 mililmeters from a diverging lens the object has a height of 13 milimeters and the image height is 3.5 milimeters how far in front of the lens is image located?
Pizza
An object is located 51 millimeters from a diverging lens the object has a height of 13 millimeters and the image height is 3.5 millimeters how far in front of the lens is image located?
Using the magnification equation m = - v / u. The image should be 13.73 mm in front of the lens
An object is located 51mm from a diverging lens the object has a height of 13mm and the image height is 3.5 how far in front of the lens is the image located?
The rays of light going through the dead centre are not deviated. So the angle from the top of image to lens centre is the same as for top of object to lens centre. So height is proportional to distance. So 13/51 = 3.5/dist giving distance=3.5x51/13 = about 13.73mm
An object is located 51 millimeters from a diverging lensthe object has a height of 13 millimeters and thye image height is 3.5 millimetershow far in front of thelens is the image located?
The relation between the distance and height of an object and the image goes like this:L1/H1=L2/H2where L1 and H1 is the Length of the object from the lens and H1 is the height of the object respectively. Same goes for L2, H2 except these are for the image of the same object.If you put values in the above formula, the distance of the image from the lens comes out to be 13.73mm
Is the type of image formed by a convex lens depend on the location of the object relative to the optical axis?
No it isn't, because the type of image a convex lens forms depends on where the object is relative to the focal point of the lens.
The function of the lens is to?
The function of lens is to to form an image of an object by converging or diverging rays of light from the object.
Why will a diverging lens never produce a real image?
A diverging lens can only produce a virtual image, because the light passing through a diverging lens never converges to a point. The virtual image produced by a diverging lens is always right-side-up and smaller than the original object. The image and the object viewed are always on the same side of the lens. Diverging lenses are used as viewfinders in cameras.
Is it possible for a diverging lens to form a real image Explain?
No, it is not possible for a diverging or a concave lens to form a real image. It always forms virtual and erect image
An object is located 51mm from a diverging lens the object has a height of 13mm and the image height is 3.5mm?
An object is located 51mm from a diverging lens the object has a height of 13mm and the image height is 3.5mm?Diverging lens do not form real images.When parallel rays of light passes thru a diverging lens, the rays diverge (spread apart) on the other side of the lens. It forms a virtual image. The object will look smaller.The image is on the same side of the lens as the object, so f is negative.Do = 51mm Ho = 13mmDi = ______ Hi = 3.5mmDi = -13.7mm1/Di + 1/Do = 1/f1/-13.5 + 1/51 = 1/ff = -18.36 mm
Which of the following is accurate in describing converging and diverging lenses?
If a single lens forms a virtual image of an object, thenthe lens could be either a diverging or a converging lens.Which statement about a single thin lens is correctA diverging lens always produces a virtual upright image.
An object 51 mililmeters from a diverging lens the object has a height of 13 milimeters and the image height is 3.5 milimeters how far in front of the lens is image located?
Pizza
An object is located 51 millimeter from a diverging lens the object has a height of 13 millimeter and the image heightg is 3.5 millimeters how far in front of the lens is the image located?
7
An object is 51 millimeters from a diverging lens the object has a height of 13 millimeters and then image height is 3.5 millimeters How far in front of the lens is the image located?
13.7 millimeters
An object located 51 millimeters from a diverging lens the object is 13 millimeters high and the image 3.5 millimeters how far in front of the lens is the image located?
13.7 millimeters
What is a negative lens is the same as?
If the lens equation yields a negative image distance, then the image is a virtual image on the same side of the lens as the object. If it yields a negative focal length, then the lens is a diverging lens rather than the converging lens in the illustration.
An object is located 51 millimeters from a diverging lens the object has a height of 13 millimeters and the image height is 3.5 millimeters how far of the lens is?
13.7 millimeters
If an object 18mm high is placed 12mm from a diverging lens and the image is formed 4mm in front of the len what is the height of the image?
6mm
