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How depleton region penetrates more in lightly doped region and less in highly doped region?
A depletion region is formed when there is a junction of p and n type semiconductor impurities. As one moves across the junction from one end to the other, one sees a change in the free carrier density from naturally high on one side to naturally low on the other. It is true of both n and p type carriers in every juntion, albeit in opposite directions. This gradient of charges can create an avalanche of current except that it is counteracted by a strong electric field at the junction; the greater the gradient of mobile charges, the larger the electric field. The region of this electric field is called the depletion region because the free electric carriers are less dense in the region than they naturally occur. The loss of these carriers leaves charged semiconductor atoms in the region in their wake. By Coulomb's law, the total number of charged atoms required is fixed by the amount of electric field and the two are proportional. Hence, in a lightly doped semiconductor, the depth to which the electric field penetrates (i.e the depth of the depletion region) is larger because the density of charged atoms is low.
What do lines represent in an electirc field diagram?
The lines in each diagram represent an electric field. The stronger the field, the close together the lines are.
How does an electric generator work?
Converts mechanical energy into electricity. Movement of magnetic field across a conductor will cause electron flow. The windings of a generator are rotated within a magnetic field.
How does Si diode work?
Crystal diode for a p-type semiconductor and n-type semiconductor formation of the pn junction, in its interface on both sides of a space-charge layer, and has a self-built electric field. When there is no applied voltage, as pn junction on both sides of carrier concentration caused by the proliferation of poor self-built electric current and drift arising from the current equivalent and the balance of power in the state. When the outside world a positive bias voltage, electric and outside the field of mutual self-suppression role of the Consumers carrier increase from the current spread of the forward current. When the outside world a reverse bias voltage, external electric field and to further strengthen self-built electric field, in a certain form of reverse voltage and reverse bias voltage value unrelated to reverse saturated current I0. When the reverse voltage applied to a certain high level, pn junction in the space charge of the electric field strength to achieve the critical values of the double-carrier process, a large amount of electronic hole right, had a great numerical breakdown of the reverse current, Breakdown phenomenon known as diodes.
What is the depletion layer in a semi conductor?
in correct sense it is not the layer but the region around the metallurgical junction which is depleted of charge carriers .in this region an internal electric field exist which counter balance the diffusion of electron and hole around the junction . basically the main reason for the formation of depletion region is the concentration gradient across metallurgical junction of p-n semiconductor.
How does the potential barrier vanishes in the transistor?
When sufficient forward voltage is applied across the junction, the electric field opposing the further diffusion of electrons from n-type to p-type semiconductor gets lost. The electric field created due to the application of the forward voltage opposes that of the barrier potential and finally vanishes the barrier completely.
Which of the following are created by an arrangement of electric charge or a current?
for apex its: a quantum field, a gravitational field
What is an electric frield?
a field of electricity created by a living organism
Can we create magnetic field to electric field?
we can create electromotive force (and electric current) by changing magnetic field linked with a conductor by the principle of electromagnetic induction which is governed by the Faraday's and Lenz's law. But electric field is created by statical electricity.
How depleton region penetrates more in lightly doped region and less in highly doped region?
A depletion region is formed when there is a junction of p and n type semiconductor impurities. As one moves across the junction from one end to the other, one sees a change in the free carrier density from naturally high on one side to naturally low on the other. It is true of both n and p type carriers in every juntion, albeit in opposite directions. This gradient of charges can create an avalanche of current except that it is counteracted by a strong electric field at the junction; the greater the gradient of mobile charges, the larger the electric field. The region of this electric field is called the depletion region because the free electric carriers are less dense in the region than they naturally occur. The loss of these carriers leaves charged semiconductor atoms in the region in their wake. By Coulomb's law, the total number of charged atoms required is fixed by the amount of electric field and the two are proportional. Hence, in a lightly doped semiconductor, the depth to which the electric field penetrates (i.e the depth of the depletion region) is larger because the density of charged atoms is low.
How do you barrier voltage is developed?
The integration of the electric field across the depletion region is what develops the barrier voltage.
Why there is no current in a metal in the absence of electric field across it?
free electron hav random motion in all posible
What will happen if no applied bias In forward bias and reverse bias?
If no forward or reverse bias is applied from outside then the diode or transistor(I'm not sure for which did you ask) is in internal equilibrium. thus there's a field created in each junction which prevents the flow of charges across it..
Why does the electric field inside a dielectric decrease when it is placed in an external electric field?
The net electric field inside a dielectric decreases due to polarization. The external electric field polarizes the dielectric and an electric field is produced due to this polarization. This internal electric field will be opposite to the external electric field and therefore the net electric field inside the dielectric will be less.
When are electronic bonds?
Are you looking for electronics bonds. Than there are mostly co-valent bond is found inside electronic component these bond are bound between carrier of that electronics device/component . they bonds are break when we applied heavy electric field across the junction and it also depend upon doping concentration.
Distinguish an electric from a magnetic field?
An electric field can created by a presence of a charge particle such as electron or proton. While a magnetic fieldis created due the relative motion of a charge particle with repeat to a stationary observer, motion of the charge particle.
Can an electric field exist without a magnetic field?
An electric field can exist even without the presence of a magnetic field. An example of this is a stationary electric field.
