The molar mass of copper is approximately 63.5 g. To find how many of these are in our sample we must divide.0.0159/63.5 = 2.5 x 10 ^ -4 = 0.00025 moles.
Each mole contains the Avogadro number of atoms, i.e. 6.023 x 10 ^ 23, so in total we have
0.00025x 6.023 x 10 ^ 23 = 1.51 x 10 ^ 20 atoms approximately.
The number of Cu atoms in the 0,0159 mol sample is 0,0957.10e23.
A mol = 6,022x10^23 atoms 1,5 mol = 9,033x10^23 atoms Always.
There are 1.204 x 1023 atoms in .200 mol of Pb.
5x10-3 g divided by m.wt. of gold (197 g/mol) equals 2.5x10-5 mol gold.2.5x10-5 mol gold multiplied by Avogadro's Number (6.023x10+23 atoms/mol) equals 1.5x10+20 atoms.
0.45 mol BaSO4 have 2,698.10e23 sulfur atoms.
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.
Approx. 9.1024 atoms.
the number of atoms is equal to the mass of the sample divided by its molar mass times one mole 11.74g / 58.69g/mol * 6.02*1023 atoms/mol = 1.2*1023 atoms approximately
1.12 x 10^22 atoms PFirst determine the number of moles in the 0.577 g sample of phosphorus, determine the number of moles in the sample. Then multiply the moles by 6.022x10^23 atoms/mol.0.577 g P x (1 mol P/30.974 g P) x (6.022x10^23 atoms P/1 mol P) = 1.12 x 10^22 atoms P
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
A mol = 6,022x10^23 atoms 1,5 mol = 9,033x10^23 atoms Always.
just divide the mass of sample by the mass of argon. OR: atomic mass of argon is 40 g/mol, so in a 40g sample of argon, there ought to be 1 mole atoms, or 6.02x10^23 atoms
Amount of Fe = 55.845/55.845 = 1mol There is 1 mol of Fe in a 55.845g sample. 1 mol of Fe contains 6.02 x 1023 atoms (avogadro constant). Therefore there are 6.02 x 1023 atoms in 55.845g of iron.
0.250 X Avogadro's Number = 1.51 X 1023, to the justified number of significant digits.
5x10-3 g divided by m.wt. of gold (197 g/mol) equals 2.5x10-5 mol gold.2.5x10-5 mol gold multiplied by Avogadro's Number (6.023x10+23 atoms/mol) equals 1.5x10+20 atoms.
1 mol of AlCl3 has mass 133.5 g and has 3 mol Cl- atoms so 400.5 g AlCl3 means 3 mol AlCl3 which means 9 mol Cl- atoms. So Ans = 9 X 6.022 X 1023 = 5.4198 X 1024 Cl- atoms
There are 1.204 x 1023 atoms in .200 mol of Pb.
There are 1.41 e24 atoms of Na in 2.35 mol of NaCl.