1.12 x 10^22 atoms P
First determine the number of moles in the 0.577 g sample of phosphorus, determine the number of moles in the sample. Then multiply the moles by 6.022x10^23 atoms/mol.
0.577 g P x (1 mol P/30.974 g P) x (6.022x10^23 atoms P/1 mol P) = 1.12 x 10^22 atoms P
In phosphorus trihydride there are four atoms. 1 x phosphorus and 3 x hydrogen. 1 + 3 = 4
tetra means four, so four
There are 4 atoms - three lithium (Li) atoms and one phosphorus (P) atom.
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
In 4PCl3 (phosphorus chloride) has 16 atoms in it. One single phosphorus chloride molecule would have four atoms in it. P=1 Cl3=3 1+3=4 4X4=16 atoms
The gram atomic mass of phosphorus is 30.9738, and by definition, a mole of such atoms contains Avogadro's Number of atoms. Therefore, 100 g of phosphorus contains 100/30.9738 or 3.23 moles, to the justified number of significant digits.
In phosphorus trihydride there are four atoms. 1 x phosphorus and 3 x hydrogen. 1 + 3 = 4
The number of phosphorus atoms is 5,326095.10e23.
4
one
The number of phosphorus atoms is 63,181.10e23.
it is 20456678
Today are known the phosphorus molecules P2 and P4.
there are 0.675moles
76
1 gram phosphorus (1mol P/30.97 grams)(6.022 X 10^23/1mol P) = 1.9 X 10^22 atoms of phosphorus
To answer this you must first be given the mass of the sample or at least percentage and molecular formula that phosphorus is in