C6H5CH=CH2 ( looks like 8 H in molecule; let's see H atoms in given mass )
5.905 grams C6H5CH=CH2 (1 mole C6H5CH=CH2/104.144 grams)(8 mole H/1 mole C6H5CH=CH2)(6.022 X 10^23/1 mole H)
= 2.732 X 10^23 atoms of hydrogen in that mass styrene
A sample of 3,2x10 atoms of nickel is equal to 0,53.10e-23 moles.
The answer is 6,31 moles Ag.
200
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
3.6 moles hydrogen atoms (1 mole water/2 mole H)(6.022 X 1023/1 mole water molecules) = 1.1 X 1024 molecules of water =======================
Approx. 9.1024 atoms.
1.7-10^24
How_many_hydrogen_atoms_are_in_5.839_grams_of_c8h8Same question answered.
Bromine is an element, and no other kinds of atoms or elements are present with it, in a pure sample.
Carbon-13 make up 1.1% of carbon atoms. .011 x 19000 carbon atoms = 209 carbon-13 atoms present.
A sample of 3,2x10 atoms of nickel is equal to 0,53.10e-23 moles.
The answer is 6,31 moles Ag.
200
They are identical.
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
Aluminum sulfide has a molar mass of 150.16 grams per mole. This means there are 0.666 moles present, or 4.01 E23 molecules. Each molecule of Al2S3 has 2 aluminum atoms, so there are 8.02 E23 atoms of aluminum present.
Which sample contains the greatest number of atoms. A sample of Mn that contains 3.29E+24 atoms or a 5.18 mole sample of I?The sample of _____ contains the greatest number of atoms.Answer:In order to compare the two samples, it is necessary to express both quantities in the same units. Since the question was phrased in terms of atoms, it is convenient to convert moles of I to atoms of I.The conversion factor between atoms and moles is Avogadro's number: 6.02 x 1023 "things" / molTo convert 5.18 moles of I to atoms of I:atoms I= 5.18 mol I6.02 x 1023 atoms I = 3.12E+24 atoms I1 mol IMultiply by atoms per mole. Moles cancel out.The sample of Mn contains 3.29E+24 atoms.Since 3.12E+24 is smaller than 3.29E+24, the sample of Mn contains the greatest number of atoms.