18
The number of address lines needed to access N-KB is given by log2N Then the number of address lines needed to access 256KB of main memory will be log2256000=18 address lines.
You need 12 address lines to access 4K of memory. 212 = 4096. log2 (4096) = 12.
you require 16 input line and 16 output line and 16 address line. Because 64 K = 26 X 210 = 216 so, 16 address lines Here N = 16, so 16 data lines will be there. .
.89 GB roughly
Microprocessor has 16 address lines and microcontroller has 20 address lines
a return address should have 2 lines
32000000 Bytes / 1024 = 31250 KBytes 31250 KBytes / 1024 = 30.5 MBytes30.5 MBytes / 1024 = 0.02978515625 ... Gigabytes
To calculate the number of address lines required for a 64 kB memory, first convert 64 kB into bytes: 64 kB = 64 × 1024 bytes = 65,536 bytes. The number of address lines needed can be determined using the formula (2^n = \text{total number of addresses}), where (n) is the number of address lines. Since 65,536 is (2^{16}), you need 16 address lines to address a 64 kB memory.
12
16KB, or 16384 bytes, can be addressed with 14 address lines. (214 = 16384)
A 2K X 8 memory requires 11 address lines and 8 data lines
In the 2k*16 , the 11 address lines are required and the 16 input-output lines are required..