7.95x10^24
To calculate the number of atoms in 13.2 mol of copper, you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole. Multiply 13.2 mol by Avogadro's number to get the number of atoms: 13.2 mol * (6.022 x 10^23 atoms/mol) = 7.93 x 10^24 atoms. Therefore, there are approximately 7.93 x 10^24 atoms in 13.2 mol of copper.
The molar mass of copper chloride is 98.999 g/mol.
12.5 (g CuCO3) = [12.5 (g CuCO3) / 123.555 (g/mol CuCO3)] = 0.1012 (mol CuCO3)0.1012 (mol CuCO3)* [1 (mol CuO) / (mol CuCO3)] = 0.1012 (mol CuO)= [0.1012 (mol CuO) * 79.545 (g/mol CuO)] = 8.047 g CuO = 8.05 g CuO
Cu2(C2H3O2)4 + 2Na2S --> 2CuS + 4Na(C2H3O2) 170 mL Cu2(C2H3O2)4 X 1 L/ 1OOO mL X .3 M/ 1 Mol X 2 Mol CuS/ 1 Mol Cu2(C2H3O2)4 X 159.157 g/ 1 Mol CuS = 16.2 g
The concentration is 2 mol/L.
Also 5,8 mol
6.022*10**23 atoms / mol = avagadro's constant 63.546 g / mol = atomic weight of copper 1 atom / 6.022*10**23 atoms/mol * 63.546 g/mol = 1.05523082*10**-22g 1 g / 63.546 g/mol * 6.022*10**23 atoms/mol = 9.476599629*10**21 atoms
The number of atoms is 39,746.10e23.
1 mol Cu Atoms (6.02x10^23 atoms)
The number of phosphorus atoms is 5,326095.10e23.
63.55 g/mol (63.55 grams per mole)
63.5 g/mol
right i dont know this 4 sure but because u want a 0.1 mol/dm3 and u only need 100cm3 u will need 0.01mols of copper sulfate to dilute in 100cm3. soo now u have a solution that is 0.01mols per 100cm3 or 0.1 mols per 1000cm3 (dm3)
The atomic weight of copper is 63,546(3).
To calculate the number of atoms in 13.2 mol of copper, you can use Avogadro's number, which is approximately 6.022 x 10^23 atoms per mole. Multiply 13.2 mol by Avogadro's number to get the number of atoms: 13.2 mol * (6.022 x 10^23 atoms/mol) = 7.93 x 10^24 atoms. Therefore, there are approximately 7.93 x 10^24 atoms in 13.2 mol of copper.
1170g
63.54 g/mol