Five. An amp (C/S) is a measure of Coulombs (C) per second (S). A coulomb is a quantity of electrons, so you can think of this as the # of electrons passing a point on a wire, like the flow of a river measured in gallons per second. A volt (J/C) is the amount of energy, measured in Joules (J), per Coulomb. Finally, a Watt (W = J/S) is the measure of energy (J) per second (S). That's why a higher wattage bulb is brighter and hotter... it's using more energy.
Therefore, Amps = W / V = (J/S) / (J/C) = (J/S) * (C/J) = C/S = 60/12 = 5
There are zero volts in 6 VA. The VA stands for Volt Amps. VA for all intents and purposes is the same as watts. You need to state an amperage to find the voltage. Volts = Watts/Amps.
What you are asking is kinda like asking how many oranges in an apple.Voltage is the measure of electrical potential.Amperage is the measure of electrical flow quantity.A good illustration is a water pipe: you can have high pressure (volts) but unless the water is allowed to flow the quantity of water is zero. (amps)
Just take the voltage and multiply it by the amps. That should give you a close approximation of the watts used. For instance, 117 volts at 4.5 amps = 5265 watts.
Light bulbs, called lamps, are run on 110 to 120 volts AC when they plug into household wiring. Other lamps use 1.5 volts, 3 volts, 4.5 volts or 6 volts DC when they are running off batteries in flashlights. Car lamps use 12 volts (though the actual car voltage is a bit more). Lamps have ratings that are specified by the manufacturers, and they have a given voltage rating based on their design. There are quite a few different lamps that come in a variety of voltage ratings.
Just use Ohm's Law: V=IR (voltage = current x resistance; using units: volts = amperes x ohms).
amps equals watts divided by volts.
Watts = Volts X Amps. Amps=Watt / Volts. So, with a 240V mains, a 60W bulb draws 0.25amps. On a 12 system (car/auto) a 60W bulb draws 5 amps. On a 110V mains, a 60W bulb draws .55 Amps.
Watts = Volts x Amps for an incandescant bulb. So Amps = 600/120.
Amps x volts = watts So, assuming you are running on 110 volt line, the answer is 65 watts/110 volts=.591 amps.
Watts = Volts x Amps x Power Factor. An incandescent light bulb is a resistive load so PF = 1. ANSWER: = 1/2 Amp
The formula is volts times amps equals watts, or watts divided by volts equals amps.
The amps drawn by a 65 watt light bulb should be 65/120 or 0.54167. This fraction of an ampere may be restated as 541.67 milli-amps.
You want to know how many amps in that circuit. To do so, divide the Watts by the Volts. in your case it would be 60 watts / 120 volts = 0.5 Amps.
If you divide the watts of the bulb by the supply voltage, that is the current. For example a 60 w bulb on a 240 v supply gives a current of 60/240 which is ¼ amp.
160 amps at 12v.
160 amps at 12v.
You have your own answer. It is 1.5 amps.