In order to answer this question, you need to know (a) its efficiency, and (b) its power factor at full load. 11 kW (not 'Kw') is its output power, so you need to know its efficiency in order to determine its input power. Then, because, for a three-phase system, power is equal to 1.732 times the product of the line voltage, line current, and power factor, you also need to know its power factor.
The line current would be the same if the motor were connected in delta. The current can be based on the rule of thumb which says 7 amps must be allowed for a 1-HP single-phase motor on 240 v. A 2.2 kW motor is three times as powerful, and on a three-phase supply of the same voltage (240/415) it would draw 7 amps.
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%
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Watts = Volts times Amps. Therefore, if the voltage was 220 volts, the motor would draw 500 amps. If the voltage was 4,000 volts, the motor would draw 27.5 amps. The voltages for large powerful motors tend to be relatively high, for example in the 380 Volts to 11,500 Volts range.
T430.247 of the NEC shows that a 1 hp motor operating at full load on 115v will draw 16 amps, called Full Load Current (FLC). Conductors supplying this motor are required to be 125% of FLC which is 20 amps. Motor circuits are complicated things and do not follow the rules of other circuits. This motor, while drawing a maximum of 16 amps at full load and supplied with #12 AWG copper conductors can be protected by a breaker of 40 amps.
A single phase 10 HP motor will draw aproximately 50 amps. A three phase 10 HP motor will draw aproximately 28 amps.
A 1-HP motor is reckoned to draw 7 amps at 240 v single-phase. The same power of motor would draw 3.5 amps at 480 v single-phase, but a 480 v supply could most likely be a three-phase suppy, and the current in that case would be reckoned as 2 amps.
read the name plate on the motor
The wiring should allow for 115 amps.
The line current would be the same if the motor were connected in delta. The current can be based on the rule of thumb which says 7 amps must be allowed for a 1-HP single-phase motor on 240 v. A 2.2 kW motor is three times as powerful, and on a three-phase supply of the same voltage (240/415) it would draw 7 amps.
Then you are trying to get more HP out of the motor that it can supply. Back off on the load that the motor is driving or put a bigger motor onto the load.
8,33 Amps
The electrical code states that a 30 HP induction motor at 460 volts three phase will draw 40 amps. <<>> I = 33.34 AMPS IF EFF.= 95% AND P.F.= 85%
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Depends on how big the motor is. A stronger motor will draw more amps then a weaker or less efficient motor. For example a wiper motor draws far less then a starter motor.
Look at the motor nameplate and it shoud have the amp draw on it. If the nameplate is missing, then the amp draw depends on what type of motor it is. The basic calculation to get you in the ball park would be as follows: 1 HP = 0.75 KW 7.5 HP = 5.63 KW Assume the efficiency of the motor is 80%, then the power supplied will need to be 5.63/0.8 = 7.04 KW amp draw = 7040/220 = 32 amps <<>> For calculation purposes the electrical code book states that a 7.5 HP motor draws 40 amps.
This depends on what voltage the range is rated for and if it is single phase or three phase. At 220 volts single phase it is about 60 amps, 240 v single phase , 53 amps and at 480 v three phase about 15 amps.